The weight of 3 heaps of gold are in ratio 5 6 7 By what fraction of themselves must the

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Previous Question: two digits selected from 0,1,2,3,4,5,6,7,8,9.slip on which code is handwritten allows confusion b/w top n bottom coz dey r indistinguishable.e.g 91 can be confused with 16. how man codes are there such dat there is no possibility of any confusion ?

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(#M40013949) MBA question set theory, logarithms, ratio proportion & variation Keep an EYE

The weight of 3 heaps of gold are in ratio 5:6:7.By what fraction of themselves must the first two be increased so that ratio changes to 7:6:5 ?Approach

1) 24/25, 2/5
2) 48/50,4,5
3) 48/50,3/5: Asked In MBA (12 years ago); Solved Dolly Read Solution (3); Is this Puzzle helpful? (33) (13) Submit Your Solution

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Maths Quotes

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How many times can you subtract 7 from 83, and what is left afterwards? You can subtract it as many times as you want, and it leaves 76 every time.

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