Latest MBA Aptitude Question SOLUTION: There are two Arithmetic Progressions A and B such that their nth terms are given by An = 101 + 3(n – 1) and Bn = 150 + (n – 1), where n is the set of natural numbers

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(#M40014049) MBA question number systems, progressions Keep an EYE

There are two Arithmetic Progressions A and B such that their nth terms are given by
An = 101 + 3(n – 1) and Bn = 150 + (n – 1), where n is the set of natural numbers. The first 50 terms
of A and B are written alternately i.e.
A1B1A2B2…..A50B50. What is the remainder when the number
so formed is divided by 11?

1) 0
2) 1
3) 9
4) 10

Asked In MBA (11 years ago)

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