Latest MBA Aptitude Question SOLUTION: Que: N=202*20002*200000002*20000000000000002*20000......2 (31 zeros).The sum of digits in this multiplication will be:

1) 112
2) 144
3) 160
4) None

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(#M40014085) MBA question number systems, progressions Keep an EYE

Que: N=202*20002*200000002*20000000000000002*20000......2 (31 zeros).The sum of digits in this multiplication will be:

1) 112
2) 144
3) 160
4) None

Asked In MBA (11 years ago)

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ANUKUL  (8 years ago)

202 = 202 (there are two 2's)

202 * 20002 = 4040404 (there are four 4's)

So, if you see, there are four 4's in the above multiplication, i.e., (number of zeroes + 1 ) number of fours.

Similarly, for 202 * 20002 * 200000002 = there will be eight 8's.

For 202 * 20002 * 200000002 * 20000 ...2 (15 zeroes) = there will be sixteen 16's.

For 202 * 20002 * 200000002 * 20000 ...2 (15 zeroes) * 2000... 2 (31 zeros) = there will be thirty two 32's.

Thirty two 32's contains thrity two 3's and thirty two 2's.
So, 32 * 3 + 32 * 2 = 160 :)

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