Latest Others Aptitude Question SOLUTION: What is the number of zeros at the end of the product of the numbers from 1 to 100?

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Previous Question: Notwithstanding all the struggle and strife looming large, the kings in this region never seem to care less for they never would give a second of their entertainment. In Phrygia for example, a game borrowed from the kings of India, involved the use of women as pieces of the board game. The board was triangular and had n points in the nth line. The women had to be placed such that no two “queens” attacked each other, the same way they would if they were on a chess board (straight and diagonally). Let g(n) = max no. of queens that could be placed on the n-triangle such that no two queens attacked each other. Your task is to find the sum of g(n) for 2 Next Question: if any one knows any simple trick to solve this question ..plz tell me.solve it without using calci... (27/9)^2*((399/39) /(41/899))

(#M40001421) OTHERS General Ability question number of zeros Keep an EYE

What is the number of zeros at the end of the product of the numbers from 1 to 100?: Asked In Others sharan reddy (13 years ago); Solved Dr.Dipin Singh Read Solution (5); Is this Puzzle helpful? (18) (6) Submit Your Solution General Knowledge

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Previous Question: Notwithstanding all the struggle and strife looming large, the kings in this region never seem to care less for they never would give a second of their entertainment. In Phrygia for example, a game borrowed from the kings of India, involved the use of women as pieces of the board game. The board was triangular and had n points in the nth line. The women had to be placed such that no two “queens” attacked each other, the same way they would if they were on a chess board (straight and diagonally). Let g(n) = max no. of queens that could be placed on the n-triangle such that no two queens attacked each other. Your task is to find the sum of g(n) for 2 Next Question: if any one knows any simple trick to solve this question ..plz tell me.solve it without using calci... (27/9)^2*((399/39) /(41/899))

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