Latest exam Aptitude Question SOLUTION: I am a rectangle. my area is 36 cm2. My lenght is 12 cm. What is my width? Explain how you decide.

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Previous Question: Verify the identity using multiple-angle formulas. 1a) cos^(2)3x-sin^(2)3x=cos6x 1b) (sin^(2)2α)/(sin^(2)α)=4-4sin^(2)α Next Question: I am using the Distributive property here, and i have to simplify each expression. This problem has me stumped. 3(e-4f-ef) Suggestions? Thank you.

(#M40146710) EXAM Numerical Ability question Keep an EYE

I am a rectangle. my area is 36 cm2. My lenght is 12 cm. What is my width? Explain how you decide.: Asked In exam (9 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: Verify the identity using multiple-angle formulas. 1a) cos^(2)3x-sin^(2)3x=cos6x 1b) (sin^(2)2α)/(sin^(2)α)=4-4sin^(2)α Next Question: I am using the Distributive property here, and i have to simplify each expression. This problem has me stumped. 3(e-4f-ef) Suggestions? Thank you.

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