An astronaut standing on the surface of the moon throws a rock upward The height of the rock is given

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Latest exam Aptitude Question SOLUTION: An astronaut standing on the surface of the moon throws a rock upward. The height of the rock is given by s=-2.7t^2+27t+6.3, where s is the height in metres and t is the time in se

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(#M40148435) EXAM Numerical Ability question Keep an EYE

An astronaut standing on the surface of the moon throws a rock upward. The height of the rock is given by s=-2.7t^2+27t+6.3, where s is the height in metres and t is the time in seconds.What was the initial height of the rock?

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