G1 a b c d e f y z and G2 a b c d e f y zIf a

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Previous Question: There are six gates in the park equidistance from each other and no more than two gets are on one straight line. All are interconnect from each other by straight lines. Find the sum of the length of roads required to connect all gates, given distance between two gates is 60m?

1) 360âˆš3 + 540
2) 1260
3) 1080
4) 480âˆš3
Next Question: How do you solve this question ?if (1+x+x^2)^6 = a0 + a1 x + a2 x^2 + ..........+ a12 x^12, then the value of 2a0 + a1 + 2a2+ a3 + 2a4 + ............. + a11 + 2a12 is

1) (3^6 + 1) / 2
2) 3(3^6 + 1) / 2
3) (3^7 + 1) / 2
4) 3(3^5 + 1) / 2

(#M40015077) MBA question algebra, quadratic equations, inequalities, functions Keep an EYE

G1 = |a|. b. |c|. d. |e|. f. ... |y|. z, and G2 = a. b. c. d. e. f. .... y. zIf a = (-1) -1, b = (-2) -2, ?.., z = (-26) -26, then

1) G1 = G2
2) G1 = -G2
3) G1 = (G2)

2

4) G2= (G1)


2


5) There is no relationship between G1 and G2: Asked In MBA (11 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Latest MBA Aptitude Question SOLUTION: G1 = |a|. b. |c|. d. |e|. f. ... |y|. z, and G2 = a. b. c. d. e. f. .... y. zIf a = (-1) -1, b = (-2) -2, ?.., z = (-26) -26, then

1) G1 = G2
2) G1 = -G2
3) G1

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(#M40015077) MBA question algebra, quadratic equations, inequalities, functions Keep an EYE

G1 = |a|. b. |c|. d. |e|. f. ... |y|. z, and G2 = a. b. c. d. e. f. .... y. zIf a = (-1) -1, b = (-2) -2, ?.., z = (-26) -26, then

1) G1 = G2
2) G1 = -G2
3) G1 = (G2)
<sup>
2
</sup>
4) G2= (G1)
<sup>
<sub>
2
</sub>
</sup>
5) There is no relationship between G1 and G2

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Latest MBA Aptitude Question SOLUTION: G1 = |a|. b. |c|. d. |e|. f. ... |y|. z, and G2 = a. b. c. d. e. f. .... y. zIf a = (-1) -1, b = (-2) -2, ?.., z = (-26) -26, then 1) G1 = G2 2) G1 = -G2 3) G1

MBA Question Papers:

Exam

MBA Question Topics

Category (7)

General Ability (7)

HR Interview (7)

Logical Reasoning (47)

Numerical Ability (171)

Programming (2)

Verbal Ability (11)

(#M40015077) MBA question algebra, quadratic equations, inequalities, functions Keep an EYE

G1 = |a|. b. |c|. d. |e|. f. ... |y|. z, and G2 = a. b. c. d. e. f. .... y. zIf a = (-1) -1, b = (-2) -2, ?.., z = (-26) -26, then 1) G1 = G2 2) G1 = -G2 3) G1 = (G2) <sup> 2 </sup> 4) G2= (G1) <sup> <sub> 2 </sub> </sup> 5) There is no relationship between G1 and G2

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Challenger of the Day

Maths Quotes

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Placement papers

Latest MBA Aptitude Question SOLUTION: G1 = |a|. b. |c|. d. |e|. f. ... |y|. z, and G2 = a. b. c. d. e. f. .... y. zIf a = (-1) -1, b = (-2) -2, ?.., z = (-26) -26, then

1) G1 = G2
2) G1 = -G2
3) G1

G1 = |a|. b. |c|. d. |e|. f. ... |y|. z, and G2 = a. b. c. d. e. f. .... y. zIf a = (-1) -1, b = (-2) -2, ?.., z = (-26) -26, then

1) G1 = G2
2) G1 = -G2
3) G1 = (G2)
<sup>
2
</sup>
4) G2= (G1)
<sup>
<sub>
2
</sub>
</sup>
5) There is no relationship between G1 and G2