Latest MBA Aptitude Question SOLUTION: A and B start simultaneously from P and Q towards Q and P respectively.The speeds of A and B are 25kmph and 32kmph resp.They meet at R and immediately return to their respective st

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(#M40015158) MBA Numerical Ability question time speed and distance, work, alligations & mixtures Keep an EYE

A and B start simultaneously from P and Q towards Q and P respectively.The speeds of A and B are 25kmph and 32kmph resp.They meet at R and immediately return to their respective starting positions after exchanging their speeds.If PQ=2000km,then the difference in times taken by A and B t reach their respective starting positions is??(Please post your approach,m getting 20 as answer )

1) 15.5 hrs
2) 20 hrs
3) 16hrs
4) 17.5hrs

Asked In MBA (11 years ago)

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Read Solution (1) :

Shruthi D  (4 years ago)

we can solve this question using the conventional method by assuming the distances to be X and (2000-X).
but an easier and faster method would be
if we consider A , who is travelling at 25 km/h from P till R then B is travelling the rest from Q to R at 25 km/h and
similarly B is travelling at 32 km/h frm Q till R then A is travelling the rest from R to P at 25 km/h
so basically the PQ distance is travelled once at 25 km/h by two different people A and B
Also PQ distance is travelled once at 32 km/h by the same A and B

so
time , T1=Distance /Speed = 2000/25 = 80 hours
time , T2 = 2000/32 =62.5 hours

difference in time = T1 -T2 = 80 - 62.5 = 17.5 hours

hope you understand :)

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