Latest A website Aptitude Question SOLUTION: Amit has a container filld completely with 80% milk and 20% water. 5 litres of the solution is removed and replaced with water. then 15litres of the solution is removed and replace

answer is 60 litre (source: bit.ly/2dFIEVU)

The capacity is 60 liters.

This is easy to check, since in the beginning there is then 48 l milk and 12 l water, then 44 l milk and 16 l water and finally 33 l milk and 27 l water, which means 55% milk.

To find the answer you use that the amount of milk scales with the milk percentage, so the following equations apply, where m is amount of milk in liters at the start, and p is percentage of milk after mixing in 5 l of water:

m / 80% = (m - 4) / p = (m - 4 - 15 p) / 55%
use outer ones to find linear relation between m and p, then make quadratic equation and solve.

IF OPTIONS GIVEN...THEN BY 60......

1 - 5/60 = 1- 1/12 = 11/12
1 - 15/60 = 1 - 1/4 = 3/4

80 * 11/12 * 3/4 = 55

Answer is 80
let capacity=x;

difference b/w milk %'s:25 i.e, 25%(x)-->20 liters of water
so capacity of container is:4*20=80liters

Let capacity =100 l
ratio of milk and water 4:1
water in 95 l = (1/5)*95=19 + 5 l added then it became 24 l.
again on finding ratio 24:76 =6:9
water in 85 l(100-15)= (6/25)*85=20.4 + 15 l water in became 35.4 l (100-35.4=64.6 milk in 100 l)
(64.6/100)=(55/x)
x=85.13 l capacity Ans

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Question
Ramesh has a container filled completely with
80
%
80% milk and
20
%
20% water.
5
5 litres of the solution is removed and replaced with water. Then,
15
15 litres of this solution is removed and replaced with water. The milk percentage is now
55
%
.
55%. Which of the following can be the capacity of the container (in litres)?
(a)
20


20 (b)
40


40 (c)
50


50 (d)
80


80 (e) None

This question is useful (2) This question is not useful (0) Comment Answer
mixtures & alligations
10 months ago, anu


1 Answer
Ans:
60
60 litre (None from the choices)

Let capacity of the container
=
x
=x
Then, initial quantity of milk
=
0.8
x
=0.8x

0.8
x
(
1
−
5
x
)
(
1
−
15
x
)
=
0.55
x
⇒
16
(
1
−
5
x
)
(
1
−
15
x
)
=
11
⇒
16
x
2
(
x
−
5
)
(
x
−
15
)
=
11
⇒
16
(
x
2
−
20
x
+
75
)
=
11
x
2
⇒
16
x
2
−
320
x
+
1200
=
11
x
2
⇒
5
x
2
−
320
x
+
1200
=
0
⇒
x
2
−
64
x
+
240
=
0
⇒
(
x
−
60
)
(
x
−
4
)
=
0
⇒
x
=
60