Latest Pratian technologies Aptitude Question SOLUTION: write a program to generate the following series.Accept the limit upto which the series needs to be generated. 1, -2, 6, -15, 31, -56,....N

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(#M40151811) PRATIAN TECHNOLOGIES Programming question test Keep an EYE

write a program to generate the following series.Accept the limit upto which the series needs to be generated.
1, -2, 6, -15, 31, -56,....N

Asked In Pratian technologies pandramish sai krishna (9 years ago)

Unsolved Read Solution (35)

Is this Puzzle helpful?   (123)   (26) Submit Your Solution Program

Read Solution (35) :

Siddharth Dwivedi  (8 years ago)

//logic is very simple..
//1, 1 + 1^2 = 2, 2 + 2^2 = 6, 6 + 3^2 = 15, 15 + 4^2 = 31, 31 + 5^2 = 56, 56 + 6^2 = 92
class number
{
public static void main(String[] args)
{
System.out.println("started!");
int n1=1,temp;

System.out.println(1);
for (int i=1;i

Is this solution Helpfull? Yes (90) | No (4)  

jeevetha  (8 years ago)

Scanner sc=new Scanner(System.in);

System.out.println("Enter the N value: ");
int N=sc.nextInt();
int sum = 1;int temp;

for(int i=0;i

Is this solution Helpfull? Yes (40) | No (7)  

sanjay  (8 years ago)

int n = 10;
int k = 1;
DataInputStream dataInputStream = new DataInputStream(System.in);
n = dataInputStream.readInt();
System.out.print(1 + ",");
for (int i = 1; i < n; i++) {
k = k + (i * i);
if (i % 2 == 0) {
System.out.print(k + ",");
} else {
System.out.print(-k + ",");
}
}

take n from user !!

Is this solution Helpfull? Yes (24) | No (6)  

Deepak Kumar Sahu  (8 years ago)

int i=1,n,j=1;
printf("Enter term no: ");
scanf("%d",&n);
while(j

Is this solution Helpfull? Yes (22) | No (6)  

tharun teja  (8 years ago)

int k = 1;
Scanner sc=new Scanner(System.in);

System.out.println("Enter the N value: ");
int N=sc.nextInt();
int sum = 1;
int temp;
System.out.print(1 + ",");
for (int i = 1; i < N; i++) {
k = k + (i * i);
if (i % 2 == 0) {
System.out.print(k + ",");
} else {
System.out.print(-k + ",");

Is this solution Helpfull? Yes (13) | No (4)  

Rajasekhar  (7 years ago)

public static void main(String[] args) throws IOException {
int n = 10;
int k = 1;
DataInputStream dataInputStream = new DataInputStream(System.in);
n = dataInputStream.readInt() ;
System.out.print(1 + ",");
for (int i = 1; i < n; i++) {
k = k + (i * i);
if (i % 2 == 0) {
System.out.print(k + ",");
} else {
System.out.print(-k + ",");
}
}

}

}

Is this solution Helpfull? Yes (5) | No   

sunil malreddy  (7 years ago)

logic is: 1+(1*1)=2,
2+(2*2)=6,
6+(3*3+=15.............and so on
#include
void main()
{
int i,j=1,n,a=1;
clrscr();
printf("enter a limit:");
scanf("%d",&n);
printf("the required series is n %dt",a);
for(i=1;i

Is this solution Helpfull? Yes (5) | No (1)  

Deepak Kumar Sahu  (8 years ago)

int i=1,n,j=1;
printf("Enter term no: ");
scanf("%d",&n);
while(j

Is this solution Helpfull? Yes (4) | No (2)  

Dilraj vyas  (8 years ago)

public class Series_New
{
public static void main(String[] args)
{
int sum=1;
System.out.println("Enter The N");
Scanner sc=new Scanner(System.in);
int N=Integer.parseInt(sc.nextLine());

for(int i=0;i

Is this solution Helpfull? Yes (3) | No (1)  

Divesh Sahu  (8 years ago)

import java.util.Scanner;
public class Series3 {
public static void main(String args[]) {
int i,a,n,temp =1;
System.out.println("Enter the number of terms upto which want to print the series:");
Scanner sc = new Scanner(System.in);
n = sc.nextInt();
for(i=0; i

Is this solution Helpfull? Yes (2) | No (2)  

Uday  (7 years ago)

//1,-2,6,-15...........
import java.util.Scanner;
public class qus1
{
public static void main(String argc[])
{
Scanner sc=new Scanner(System.in);
int n,i,res=1;
System.out.print("Enter number n : ");
n=sc.nextInt();


System.out.print(res);

for(i=1;i

Is this solution Helpfull? Yes (2) | No   

Prince Pandey  (7 years ago)

/*
write a program to generate the following series.
1, -2, 6, -15, 31, -56,....
*/
import java.util.Scanner;
class Series2{
public static void main(String[] args){
Scanner scan = new Scanner(System.in);
System.out.println("Enter limit of sequence:");
int n = scan.nextInt();
int first = 1, result = 0;
for(int i = 0; i < n; i++){
result = first + (i*i);
if(i%2 != 0)
System.out.print((-result) + " ");
else
System.out.print(result + " ");
first = result;
}
}

}

Is this solution Helpfull? Yes (2) | No (1)  

PHANI CHAND TEKKEM  (8 years ago)

int N, k=2, res = 1;

N = Convert.ToInt32( Console.ReadLine( ) );
for( int i = 1; i

Is this solution Helpfull? Yes (1) | No   

venugopal reddy  (8 years ago)

int pepper =1 ;
int i , j, limit ;
printf ("Enter the limit value : ") ;
scanf ("%d", &limit ) ;

for (i=1 , j=1 ; i < limit ; j++ )
{
printf ("%d, " ( j%2 ) ? i : -i ) ;
i += pepper ;
pepper = pow ( j , 2 ) ;

}

Is this solution Helpfull? Yes (1) | No (1)  

akhilesh kumar  (7 years ago)

import java.util.Scanner;
public class B {

public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println("Enter How Many Number You Want... ");
Scanner sc = new Scanner(System.in);
int num = sc.nextInt();
int sum =1;
int result =1;

for (int i = 1; i

Is this solution Helpfull? Yes (1) | No   

amit kumar  (7 years ago)

import java.util.*;
public class amitraj {
public static void main(String[] args) {
Scanner a = new Scanner(System.in);
int b=a.nextInt();

int l=0;
int o=1;
System.out.println(o);


for(int k=1;k

Is this solution Helpfull? Yes (1) | No (2)  

Sushree Manisha Sahoo  (7 years ago)

import java.util.Scanner;

public class Series {

public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scn = new Scanner(System.in);
System.out.println("Enter range");
int n = scn.nextInt();
int a = 1;
int count = 0;
for(int i = 1;count

Is this solution Helpfull? Yes (1) | No   

Arnab Datta  (5 years ago)

#include
int main()
{
int i,k=1,n;
printf("Enter the number of terms : ");
scanf("%d",&n);
printf("1 , ");
for (i = 1; i < n; i++)
{
k = k+(i*i);
if (i % 2 == 0)
printf("%d ,",k);
else
printf("%d ,",-k);
}
return 0;
}

Is this solution Helpfull? Yes (1) | No   

Dhanunjaya Gattu  (8 years ago)

public class Series {

public static void main(String[] args) {
int n = 50;
int num=0,j;
int ser = 1;

for(int i=1;i

Is this solution Helpfull? Yes | No   

Dhanunjaya Gattu  (8 years ago)

for(int i=1;i

Is this solution Helpfull? Yes | No (2)  

Santosh  (8 years ago)

int n=1;
for (int i=0;i

Is this solution Helpfull? Yes | No   

venugopal reddy  (8 years ago)

int pepper =1 ;
int i , j, limit ;
printf ("Enter the limit value : ");
scanf ("%d", &limit ) ;

for (i=0 , j=0 ; i < limit ; j++ )
{
printf ("%d, " (j%2)? i : -i ) ;
i += pepper ;
pepper = pow( pepper+1 , 2 ) ;

}

Is this solution Helpfull? Yes | No (3)  

bhavya  (8 years ago)

x=0,f=1,k=1
for(i=1,i

Is this solution Helpfull? Yes | No   

umesh  (8 years ago)

class Test1{
public static void main(String[]args){
int n=Integer.parseInt(args[0]);
int s=1;
System.out.print(s);
for(int i=1;i

Is this solution Helpfull? Yes | No   

Abhishek kumar keshri  (8 years ago)

#include


int main()
{
int sum=1;
for(int i=0;i

Is this solution Helpfull? Yes | No (1)  

md wasi ahmed ansari  (7 years ago)

#include
#include
void main()
{
int i,n;
printf("Enter the no of termsn");
scanf("%d",&n);
int k=1;
printf("%dt",1);
for(i=1;i

Is this solution Helpfull? Yes | No   

vivek sharma  (6 years ago)

#include
#include
int main()
{

int a=1,b=0,i=1,p[10];

p[0]=a;
while(i

Is this solution Helpfull? Yes | No   

harishreddy  (6 years ago)

package Series;

/////1,-2,6,-15,31,-56,....N
public class SeriesA {
public static void main(String[] args) {
//int n;
int f1 = 1;
for(int i=1;i

Is this solution Helpfull? Yes | No   

victor sam  (6 years ago)

#include
int main(){
int sum=0,n,sum1=2;
scanf("%d",&n);
for(int i=2;sum1

Is this solution Helpfull? Yes | No   

  (6 years ago)

import Java.util.scanner;
class Test1
{
Public static void main(string [] args)
{
int k=1;
Scanner s= new Scanner(System.in);
System.out.print("Enter the N value:");
int n= s.nextInt();
System.out.print(1+",");
for(int i = 1;i

Is this solution Helpfull? Yes | No   

  (6 years ago)

//developer ruhul amin choudhury
//time : 04:46 AM

#include
#include
int main()
{
int end_term , ans = 1 , i ;
scanf("%d",&end_term);
if(end_term == 1)
printf("1n);
else
{
printf("1 ") ;
for(i = 1 ; i < end_term ; i++)
{
if( (i+1) < 4)
ans = i + ( i * i ) ; // for 1 -2 6 values
else
ans = ans + (i * i ) ; // for -15 31 -56 to .... end terms or last term
if( i %2 != 0 )
printf(" - %d " ,ans);
else
printf("%d " ,ans );
}
}
return 0 ;
}

Is this solution Helpfull? Yes | No   

Ganga  (6 years ago)

class Test1{
public static void main(String args[]){

int start=1;
System.out.print(start+"t");
int a=1;

for(int i=1; i

Is this solution Helpfull? Yes | No   

Rutuja Ramji Banswal  (6 years ago)

this code works
#include

int main()
{
int n=10,k=1,i;
printf("Enter n : ");
scanf("%d",&n);

for(i=0;i

Is this solution Helpfull? Yes | No   

  (5 years ago)

package javasorting;
import java.util.Scanner;


public class SpecialSeries2 {
public static void main(String[] args) {
double a=1;
Scanner kb= new Scanner(System.in);
System.out.println("Enter size of a series");
int sizeOfSeries =kb.nextInt();
System.out.print((int)a+" ");
int count=1;
for(int i=1;i

Is this solution Helpfull? Yes | No   

Arnab Datta  (5 years ago)

#include
int main()
{
int i,k=1,n;
printf("Enter the number of terms : ");
scanf("%d",&n);
printf("1 , ");
for (i = 1; i < n; i++)
{
k = k+(i*i);
if (i % 2 == 0)
printf("%d ,",k);
else
printf("%d ,",-k);
}
return 0;
}

Is this solution Helpfull? Yes | No   

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