Latest Gate Aptitude Question SOLUTION: the probability that there are 53 sundays in a randomly chosen leap year

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(#M40151815) GATE General Ability question probability Keep an EYE

the probability that there are 53 sundays in a randomly chosen leap year

Asked In Gate mahendrakumar (9 years ago)

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varun  (9 years ago)

assuming 52 sundays in a year are their ... it makes
52 X 7=364 days

now the remaining 2 days one of the day might be sunday

the probability will be 2/7= 0.28

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kishor Mali  (9 years ago)

2/7 ....bcoz in a leap year their is 2 odd days....so it may be (sun mon) or (mon tues) and so on...so out of 7 days fav cases are 2...2/7 is ans

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anuanwesh  (8 years ago)

2/7 52*7=364 2 odd days rem they can be any of 7 so 2 out of 7 ie 2/7

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TEJA KRISHNA BABU PENTAKOTI  (8 years ago)

Our sample space is S : {Monday-Tuesday, Tuesday-Wednesday, Wednesday-Thursday,..., Sunday-Monday}
Number of elements in S = n(S) = 7
What we want is a set A (say) that comprises of the elements Saturday-Sunday and Sunday-Monday i.e. A : {Saturday-Sunday, Sunday-Monday}
Number of elements in set A = n(A) = 2
By definition, probability of occurrence of A = n(A)/n(S) = 2/7

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N.Vennela Rani  (8 years ago)

2/7
in leap year 366 days.in that 52 sundays are there and two days will remain

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monu kumar  (8 years ago)

366 days in leap year in which 52w and 2d[(sun,mon) (mon,tue) (tue,thu,) (wed,thu) (thu,fri) (fri,sat)and(sat,sun)].so answer is 2/7

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