Latest Accenture Aptitude Question SOLUTION: two urns contain respectively 2 red 3 white and 3 red,5 white balls.One ball is drawn at random from the first urn and transferred into the second.A ball is now drawn from the seco

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two urns contain respectively 2 red 3 white and 3 red,5 white balls.One ball is drawn at random from the first urn and transferred into the second.A ball is now drawn from the second urn and it turns out to be red.What is the probability that the transferred ball was white?

Asked In Accenture Rahul shaw (8 years ago)

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chandra kishor  (8 years ago)

according to baye,s theorem
p(no of way to drawn a ball from 2nd urns is red and ball transferred from 1 urns)=(3c1/5c1)*(3c1/9c1)=9/45
total=(2c1/5c1)*(4c1/9c1)+(3c1/5c1)*(3c1/9c1)=17/45
so probablity=9/45/17/45=9/17;

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Rahul shaw  (8 years ago)

Sorry Pratibha...Correct answer is 9/17

Is this solution Helpfull? Yes (8) | No (1)  

Deeksha Joshi  (8 years ago)

3C1/5C1=3/5

Is this solution Helpfull? Yes (3) | No (9)  

Priya Agarwal  (8 years ago)

when ball transfered from 1st urn is red, no of red and white balls in 2nd urn is 4 & 5 respectively.
if ball transferrd is white , then no of red and white balls is 3 & 6 respectively.
probability of drawing red ball is(4/9+3/9)=7/9
according to bayes theorem, probability that transferd ball is white=(3/9)/(7/9)=3/7
so, answer=3/7

Is this solution Helpfull? Yes (2) | No (4)  

pratibha sharma  (8 years ago)

red=2/5
then second red=3/8
total=3/8+2/5
31/40
ans=1-31/40=9/40

Is this solution Helpfull? Yes (1) | No (8)  

akshay  (8 years ago)

3/5
i think if ball is drawn from the second urn it doesnt mattr the first urn its probability remain same

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Ankit Sekhri  (8 years ago)

P(transferring white ball) =3/5
After transfer we will have 3 red and 6 white balls in 2nd urn.
P(selecting red ball) = 3/9= 1/3
P(both events happening) = 3/5* 1/3 = 1/5

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