Latest Elitmus Aptitude Question SOLUTION: there is a cask full of milk. E litres of milk are drawn from the cask and replaced with water. this process is repeated. now ratio of milk and water is 16:9. what is the capacity

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(#M40152323) ELITMUS Numerical Ability question Raton and propotion Keep an EYE

there is a cask full of milk. E litres of milk are drawn from the cask and replaced with water. this process is repeated. now ratio of milk and water is 16:9. what is the capacity of the cask in litres?
1. E+9
2. 5E
3. 9E
4. cannot be determined

Asked In Elitmus Souradeep Guhathakurta (8 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

Anamika  (8 years ago)

let x be the initial qty.
after one replacement proportional of milk left x-e/x,after two (x-e/x)^2,
the ratio is given as 16:9 i.e milk to water ratio,milk would be 16/25
(x-e/x)^=16/25
x-e/x=4/5
1-(e/x)=4/5
1-4/5=e/x
1/5=e/x
x=5E
i think the process is done two times..

Is this solution Helpfull? Yes (17) | No (4)  

pradeep singh rawat  (8 years ago)

ans is 5E.

Is this solution Helpfull? Yes (1) | No   

kundan prasad  (8 years ago)

Ans: 2)5E

Is this solution Helpfull? Yes (1) | No   

Shiva Shankar  (8 years ago)

The ratio is given as 16:9.
let x be the initial qty and assume that the process done in 2 times.
after one replacement proportional of milk left x-e/x,after two (x-e/x)^2,
the ratio is given as 16:9 i.e, milk to water ratio,milk would be 16/9.
(x-e/x)^2=16/9
x-e/x=4/3 [take x=1]
=> 1-(e/x)=4/3
1-4/3=e/x
-1/3=e/x
x=-3E.
for 2 times of this process repetition the answer is '-3E'. similarly, for 3 or more times of repetition of this process, the answer should be decimal multiples of E (example: 2.1467E).
So the answer should be in negative or in decimal points only. So, there is no option like that (Because 'E' multiplied by negative value or fraction only).
So, definitely, the answer should be "cannot be determined".

Is this solution Helpfull? Yes | No (3)  

vishwa  (8 years ago)

its 100% cannot be determined because 5E represents 5 timess of E quantity which is impossible and 3E represents the same E+9 is also impossible because already cask is full so E+9 is also impossible so the answer is D

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priyanka  (7 years ago)

my Answer is 4 coz we replace the e litres from cask nd we dont know what is E nd what is the capacity of E

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Swaroop Kumar S C  (7 years ago)

((x-e)/x)^2 = 16/25
(x-e)/x = 4/5
1-(e/x) = 4/5
1-(4/5) = e/x
1/5 = e/x
x = 5e

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