Latest Wipro Aptitude Question SOLUTION: select a number between 1 to 99999999. write a program in java so that you can receive a number and calculate its frequency in that given number. (Eg: 2 in 12521222 ans: 5)

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select a number between 1 to 99999999. write a program in java so that you can receive a number and calculate its frequency in that given number.
(Eg: 2 in 12521222 ans: 5)

Asked In Wipro Pragnyananda Mishra (8 years ago)

Unsolved Read Solution (3)

Is this Puzzle helpful?   (2)   (1) Submit Your Solution Mathematical Reasoning

Read Solution (3) :

sonu  (5 years ago)

import java.util.*;
class test12
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
int number,k,count=0,result=0;
System.out.println("Enter no between 1 to 99999999999");
number=sc.nextInt();
System.out.println("Enter no to be checked");
k=sc.nextInt();
while(number>0)
{
result=number%10;
number=number/10;
if(result==k)
count++;
}
System.out.println(count);
}
}

Is this solution Helpfull? Yes (3) | No   

bojanapu prashanthi  (8 years ago)

#include
main(){
int i,j,k,n,c=0;
printf("Enter any number blw 1 and 99999999n");
scanf("%d",&n);
printf("Enter the number to find the frequencyn");
scanf("%d",&k);
for(i=0;i

Is this solution Helpfull? Yes (1) | No (5)  

  (6 years ago)

import java.util.Scanner;

public class NumberFrequency
{
public static void main(String[] args)
{
Scanner ac = new Scanner(System.in);
System.out.println("Enter No. 1 to 99999999 :- ");
long value = ac.nextLong();
long number = value;

System.out.println("Enter No. ye want check Frequency:- ");
int no = ac.nextInt();
int check = 0;
int digit = 0;


for (int i=0; i8)
{
System.err.println("Exceed Digit Limit......");
System.exit(0);
}
int[] range = new int[digit];
number = value;

for (int i=(digit-1); i>=0 ; i--)
{
range[i] = (int) (number%10) ;
number = number/10 ;
}

for (int j=0; j

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