Latest Wipro Aptitude Question SOLUTION: The minimum number of numbers required to form a number from 9 to 9000 which are multiples of 5 is: a) 31 b) 41 c) 42 d) 32

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(#M40153006) WIPRO Logical Reasoning question Keep an EYE

The minimum number of numbers required to form a number from 9 to 9000 which are multiples of 5 is:

a) 31 b) 41 c) 42 d) 32

Asked In Wipro Sushmitha (8 years ago)

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Sushmitha  (8 years ago)

The multiples of 5 must end with 0 or 5.
Therefore, units place of a number from 9 to 9000 can be filled by only two digits 0 and 5. i.e., 2 digits.
10's place of a number from 9 to 9000 can be formed by 0 to 9 digits. i.e., 10 digits.
100's place of a number from 9 to 9000 can be formed by 0 to 9 digits. i.e., 10 digits.
1000's place of a number from 9 to 9000 can be formed by by 1 to 9 digits 1. i.e., 9 digits.
Therefore, total number of numbers required is 2 + 10 + 10 + 9 = 31.

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Nukala  (8 years ago)

31 is aswer

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