Latest TCS Aptitude Question SOLUTION: in how many ways can the letter of english alphabet be arranged so that there are seven letters between the letter A and B and no letter is repeated

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in how many ways can the letter of english alphabet be arranged so that there are seven letters between the letter A and B and no letter is repeated

Asked In TCS harshita shewani (8 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Chenna Reddy   (8 years ago)

Answer is 24c7*7!*2
Reason: REMAINING alphabets excluding A ,B=24
7 alphabets should be arranged in btwn A & B,means 24c7 combination or selection are possible=> A*******B = 24c7 ways.
now the selcted alphabets themselves can b arranged in 7! ways =>24C7*7!
Finally they said in between A and B So another possible which dobles the count is B*******A =24c7*7!
SO, ans is 24c7*7!*2

Is this solution Helpfull? Yes (10) | No (2)  

SHIBAJI bOSE  (8 years ago)

24p7*2!*18!

Is this solution Helpfull? Yes (7) | No (3)  

Gaurav Maderna  (8 years ago)

7 alphabets are to be placed in btw A and B.
Numbers of ways are=24*23*22*21*20*19*18.
Since A and B are fixed so remained alphabets are 24.

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gourav  (8 years ago)

Ans is 24p7*2!*18! , it is because excluding A and B we have 24 letters and we have to find arrangements of 7 letters , it is multiplied by 2 because A and B can be arranged in 2! ways and again multiplied by 18 because 26-2-7+1 =18

Is this solution Helpfull? Yes (4) | No   

Tuhin Barai  (8 years ago)

36*24! Is the correct answer , tally with anyone

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rabi  (8 years ago)

24c7*7!*2!

Is this solution Helpfull? Yes (2) | No   

aditi yadav  (8 years ago)

2*7!*18! -ans
we will consider 2*7! as one box and internally we will arrange it in this way now we will be left with 18 alphabet including the box so the way to arrange them will be 18!

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Aswarthama Reddy  (8 years ago)

24c7
remaining numbers 24 and places 7

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