Latest Elitmus Aptitude Question SOLUTION: A cask full of milk,'E' liters is removed and water is mixed. This process is repeated and now the ratio in milk to water is 16:9. Then what is the amount of milk in liter. E+9 9E

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A cask full of milk,'E' liters is removed and water is mixed. This process is repeated and now the ratio in milk to water is 16:9. Then what is the amount of milk in liter.
E+9 9E 5E cant be determined

Asked In Elitmus Malaya Prasad Lenka (8 years ago)

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Ajitesh rai  (8 years ago)

Ans is 5E...
EXPLANATION-------------

After 'n' operations ,the amount of pure liquid remaining is = [x { ( 1-E/x )^n } ]...where x is original amount of liquid and E is amount of liquid removed..This is standard formula in RS aggarwal...

Now ,in our case the operations is performed twice...

Let the original milk be x liters..

E liters removed twice n = 2,

milk remaining (M) = [ x { (1-E/x)^2 } ]....water is (W) = x - [x { (1-E/x)^2 } ]

M/W = 16/9 Take (1-E/x)^2 = z

now solving we get z = 16/25 that is (1 - E/x)^2 = (4/5)^2

1 - E/x = 4/5

x = 5E (Answer)

Is this solution Helpfull? Yes (22) | No   

Mrityunjay Kaushik  (8 years ago)

5E
......................
suppose initially milk was X
now after process
milk=k(1-E/k)^2...........eq
water_remained=k-milk......eq
eq/eq=16/9
k=5E

Is this solution Helpfull? Yes (1) | No (1)  

vadicharla sagar ramulu  (8 years ago)

i think cant be determined is ans.

Is this solution Helpfull? Yes | No (7)  

Harshvardhan kumar  (8 years ago)

can't be determine..

Is this solution Helpfull? Yes | No (2)  

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