Latest Accenture Aptitude Question SOLUTION: ind the numbers between 100 to 400 which is divisible by either 2,3,5,7...

lcm of 2,3,5,7=210

Total number of numbers between [a,b] (i.e. from a up to b)divisible by a number x=⌊ax⌋−⌈bx⌉+1

Following the above,

Total number of numbers between 100 to 400 is divisible by 2 = 151
Total number of numbers between 100 to 400 is divisible by 3 = 100
Total number of numbers between 100 to 400 is divisible by 5 = 61
Total number of numbers between 100 to 400 is divisible by 7 = 43



Total number of numbers between 100 to 400 is divisible by 2x3 = 50
Total number of numbers between 100 to 400 is divisible by 2x5= 31
Total number of numbers between 100 to 400 is divisible by 2x7 = 21
Total number of numbers between 100 to 400 is divisible by 3x5 = 20
Total number of numbers between 100 to 400 is divisible by 3x7 = 15
Total number of numbers between 100 to 400 is divisible by 5x7 = 9

Total number of numbers between 100 to 400 is divisible by 2x3x5 = 10
Total number of numbers between 100 to 400 is divisible by 2x3x7= 7
Total number of numbers between 100 to 400 is divisible by 2x5x7 =4
Total number of numbers between 100 to 400 is divisible by 3x5x7 = 3

Total number of numbers between 100 to 400 is divisible by 2x3x5x7 = 1
Thus, the answer is
(151+100+61+43)−(50+31+21+20+15+9)+(10+7+4+3)−1=232

lcm of 2,3,5,7 (2*3*5*7)=210 is ans

The correct answer is 210. The question is which no. is divisible by either 2,3,5,7 between 100 to 400?. so i you take lcm, that would be the answer.

total no bw 100 and 400 are 300
so 300/2 = 150
300/3 = 100 but some no. are there which can be devided by 2 also so 50
300/5 = 60 but some no. are devided by 2 n 3 also so 12
300/7=42 but no devided by 2,3 ,5 also so 9
total no. is= 150 +50+12+9 =221

(150+100+60+42-50-12-9-1)=280

@gourav_kapoor, can you explain the steps in details?

i could not get your solution Gourav...plzz explain a little bit more.

the numbers bw 100 to 400 which are devisible by either 2,3,5,7 means lcm of those 2,3,4,7

232 is the answer