Latest TCS Aptitude Question SOLUTION: 2. What is the sum of the squares of the first 20 natural numbers (1 to 20)? a) 2870 b) 2000 c) 5650 d) 44100

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(#M40153481) TCS Numerical Ability question based sum of squares of first N natural numbers Keep an EYE

2. What is the sum of the squares of the first 20 natural numbers (1 to 20)?

a) 2870

b) 2000

c) 5650

d) 44100

Asked In TCS J E Tejeswar Gowd (8 years ago)

Solved gourav Read Solution (25)

Is this Puzzle helpful?   (55)   (16) Submit Your Solution Arithmetic

Read Solution (25) :

Lakshmipathi Bojanapu  (8 years ago)

n(n+1)(2n+1)/6
20(21)(21)/6
=2870

Is this solution Helpfull? Yes (13) | No (7)  

gourav  (8 years ago) Best Solution

it will be option a. using the formula n*(n+1)*(2n+1)/6 => 20*21*41/6=2870

Is this solution Helpfull? Yes (9) | No (1)  

G.NAGAMANI  (8 years ago)

The sum of squares in natural n is=n(n+1)(2n+1)/6
i,e=20*21*41/6
=2870

Is this solution Helpfull? Yes (2) | No   

madhusudhan reddy  (8 years ago)

use sum of squares Formula:n*(n+1)*(2n+1)/6
n=20,answer=2870 (option A)

Is this solution Helpfull? Yes (1) | No (1)  

Sanket  (8 years ago)

n/6*(n+1)*(2n+1)=2870

Is this solution Helpfull? Yes (1) | No   

gourav  (8 years ago)

it will be option a. using the formula n*(n+1)*(2n+1)/6 => 20*21*41/6=2870

Is this solution Helpfull? Yes | No   

Himanshu Pant  (8 years ago)

Use this formula n*n+1*2*n+1/6
so ans is 2870

Is this solution Helpfull? Yes | No   

pooja singh  (8 years ago)

sum=n(n+1)(2n+1)/6=2870

Is this solution Helpfull? Yes | No (1)  

Thamizhiniyan.P  (8 years ago)

20(21)(21)/6=2870

Is this solution Helpfull? Yes | No (1)  

prathyusha  (8 years ago)

a sum of the squares formula n(n+1)(2n+1)/6

Is this solution Helpfull? Yes | No   

Apurva ANAND  (8 years ago)

n(n+1)(2n+1)/6
=20*21*41/6
=2870

Is this solution Helpfull? Yes | No   

Deepak gautam  (8 years ago)

n(n+1)(2n+1)/6

Is this solution Helpfull? Yes | No   

Ravi bisariya  (8 years ago)

n(n+1)(2n+1)/6
20(20+1)(41)/6
=2870

Is this solution Helpfull? Yes | No   

velmala gangadhar  (8 years ago)

a...2870.........n(n+1)(2n+1)/6....

Is this solution Helpfull? Yes | No   

NAVEEN   (8 years ago)

sum of squares of first n natural number is n(n+1)(2n+1)/6
so n=20
if we substitute we'll get 2870 as ans

Is this solution Helpfull? Yes | No   

Babu  (8 years ago)

1+10=55
11+20=155
55+155=210
210^2=44100

Is this solution Helpfull? Yes | No (1)  

Abhisek Ghosh  (8 years ago)

1/6*n*(n+1)*(2n+1)....20*21*41/6

Is this solution Helpfull? Yes | No   

Priya bogra  (8 years ago)

a..by using formula n(n+1)(2n+1)/6

Is this solution Helpfull? Yes | No   

syed sakirhusain nasirhusain  (8 years ago)

answer is 2870

Is this solution Helpfull? Yes | No (2)  

shalini kumari singh  (8 years ago)

sum of squares of first n natural nos=(n(n+1)(2n+1))/6
so required sum=(20(20+1)(2*20+1))/6=2870

Is this solution Helpfull? Yes | No   

Kritika Goyal  (7 years ago)

Use the formula for the summation of squares of first n natural numbers: n(n+1)(2n+1)/6
On substituting the value of n as 20 in this case, we get the answer as 2870.

Is this solution Helpfull? Yes | No   

PRIYA  (6 years ago)

option a is the answer
sum of squares of 1st n natural numbers={n*(2n+1)*(n+1)}/6
={20*21*41}/6
=2870

Is this solution Helpfull? Yes | No   

Akash Sharma  (5 years ago)

n(n+1)(2n+1)/6
20(21)(21)/6
=2870

Is this solution Helpfull? Yes | No   

Akash Sharma  (5 years ago)

n(n+1)(2n+1)/6
20(21)(21)/6
=2870

Is this solution Helpfull? Yes | No   

DIVYA NAGUMALLI  (4 years ago)

The sum of squares of n natural numbers is:=n*(n+1)*(2 n+1)/6
=>20*(20+1)*(2*20+1)/6
=>(20*21*41)/6
=2870

Is this solution Helpfull? Yes | No   

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