Latest TCS Aptitude Question SOLUTION: In this problem, ABS(x) provides absolute value of x, without regard to its sign. For example ABS(3) = ABS(-3) = 3 The graphs of y = – ABS(x – a) + b and y = ABS(x – c) + d

• Placement Papers
• /
• TCS
• /
• Programming
• /
• Functions

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40153514) TCS Programming question Keep an EYE

In this problem, ABS(x) provides absolute value of x, without regard to its sign. For example ABS(3) = ABS(-3) = 3
The graphs of y = – ABS(x – a) + b and y = ABS(x – c) + d intersect at points (2,5) and (8, 3).
Find a + c
a. 8
b. 10
c. 7
d. 5

Asked In TCS (8 years ago)

Unsolved Read Solution (2)

Is this Puzzle helpful?   (8)   (16) Submit Your Solution Functions

Read Solution (2) :

arpit mathur  (8 years ago)

Both curves intersect at (2, 5)
So 5 = – |2 – a| + b ⇒ 5 + |2 – a| – b = 0 - - - (1)
5 = – |2 – c| + d ⇒ 5 + |2 – c| – d = 0 - - - (2)
Also,
3 = – |8 – a| + b ⇒ 3 + |8 – a| – b = 0 - - - (4)
3 = – |8 – c| + d ⇒ 3 + |8 – c| – d = 0- - - (4)
Equating 1 and 3, 5 + |2 – a| = 3 + |8 – a| ⇒ 2 + |2 – a| = |8– a|
So a = 4
Similarly if we equate 2 and 4, we get c = 4
a + c = 8

Is this solution Helpfull? Yes (8) | No (18)  

prakhar  (8 years ago)

10 hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Is this solution Helpfull? Yes (1) | No (5)  

Please Login to Read Solution.