Latest Accenture Aptitude Question SOLUTION: Three runners A, B and C run a race, with runner A finishing 12 meters ahead of runner B and 18 meters ahead of runner C, while runner B finishes 8 meters ahead of runner C. Each r

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(#M40153545) ACCENTURE Numerical Ability question Keep an EYE

Three runners A, B and C run a race, with runner A finishing 12 meters ahead of runner B and 18 meters ahead of
runner C, while runner B finishes 8 meters ahead of runner C. Each runner travels the entire distance at a constant
speed. What was the length of the race?
a)36 meters b)48 meters c)60 meters d)72 meters

Asked In Accenture preethy vijayakumar (8 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

Suman Sourabh  (8 years ago)

Ans: 48M
Let the length of race is X meter.
when A is on X meter, then B is on X-12 and C is on X-8.
Now,
if B is on X-12 meter then C is on X-18 meter
so if B is on 1 meter then C is on (X-18)/(X-12) meter
So if B is on X meter then C is on ((X-18)/(X-12))*X meter
and it is given that if B is on X meter then C is on X-8 meter
So ((X-18)/(X-12))*X = X-8
Solve it and get the value of X as 48 meter

Is this solution Helpfull? Yes (19) | No (1)  

neha  (7 years ago)

Let distance of race be x mtrs. Then when A finishes x m , B has run (x- 12)mtrs and C has run x-18 mtrs. so at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, so he runs another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.

as speeds are constant, we have equation,

x-12/ x-18 = 12/10 > x = 48.

Answer B

Is this solution Helpfull? Yes (3) | No (1)  

hemant kumar  (8 years ago)

answer id B

Is this solution Helpfull? Yes (1) | No (4)  

vamshi krishna  (8 years ago)

ans is d.

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