Latest TCS Aptitude Question SOLUTION: The average temperature of June, July and August was 31 degrees. The average temperature of July, August and September was 30 degrees. If the temperature of June was 30 degrees, fi

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The average temperature of June, July and August was 31 degrees. The average temperature of July, August and September was 30 degrees. If the temperature of June was 30 degrees, find the temperature of September (in degrees).

option:
a.25
b.26
c.27
d.28

Asked In TCS aafila (8 years ago)

Unsolved Read Solution (22)

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Read Solution (22) :

Mangesh Shinde  (8 years ago)

c.27

June+July+August=3*31=93.......(1)
July+august+Sept=3*30=90........(2)
June=30

Hence, putting june =30 in equ 1

July+August=63

putting in 2nd equ.
63+Sept=90

hence, Sept=27

Is this solution Helpfull? Yes (16) | No   

Tuhin Barai  (8 years ago)

June + July + August = 93 ( Total )
Juky + August + Sept. = 90 (Total)
------------------------------------------
(Minus)
June - Sept. = 3
30 - Sept = 3
Or, 30-3=Sept which will be 27.

Is this solution Helpfull? Yes (5) | No   

Arun  (8 years ago)

(june+july+aug)/3=31
(july+aug+sep)/3=30
given that
june=30
let july=31,aug=32
now,(31+32+sep)/3=30
sep=90-63
sep=27

Is this solution Helpfull? Yes (2) | No   

abcd  (8 years ago)

june+july+agust=93--------(1)
july+agust+sept=90------------(2)
(1)-(2)=>june-sept=3
given june=30
sept =30-3=27

Is this solution Helpfull? Yes (2) | No   

Anik Bhattachaya  (8 years ago)

June + july + august = 31x3 = 93
given, june =30
thus, july+august=93-30=63

now given , july + august +sept = 30x3 = 90
so,
sept= 90 - (july+august) = 90 - 63 = 27

thus (C)

Is this solution Helpfull? Yes (2) | No   

aswathi  (8 years ago)

June+July+august=31*3=93
June+July+August+September= 30*4=120
Temp of September= 120-93=27

Is this solution Helpfull? Yes (2) | No   

lavanya vaithilingam  (8 years ago)

answer is c.27
june +july+aug=31(30)=93
july+aug+sep=30(3)=90
gn:june=30
in 1 st eq july +aug=93-30=63
in 2nd eq 63+sep=90
sep=90-63=27

Is this solution Helpfull? Yes (2) | No   

naina dubey  (8 years ago)

june+july+august=93
june+july+september=90
now subtract above two eqaution we get
june-september=3
now value of temp in june is=30
so after puting the value of june we got tep of september is eqaul to 27 i.e answer

Is this solution Helpfull? Yes (2) | No   

MallikarjunaReddy Tippareddy  (8 years ago)

let take june as jn;july as jl;august as a;september as s;
(jn+jl+a)/3=31
given jn=30;
jl+a=93-30=>jl+a=60;
(jl+a+s)/3=30;
s=90-(jl+a)=>90-63
september temperature is 27

Is this solution Helpfull? Yes (2) | No   

Amit  (8 years ago)

june+july+august=3*31=93
july+august+september=3*30=90
and june=30
so,
july+august=93-30=63

so,
july+august+september=90
63+september=90
september=90-63=27

Is this solution Helpfull? Yes (1) | No   

p.varuunkumar  (8 years ago)

27 degrees because (june+july+aug)/3=31,(july+aug+sep)/3=30 solving we get 27

Is this solution Helpfull? Yes (1) | No   

Aritra Chakraborty  (8 years ago)

(jun(=30)+jul+aug)/3=31 => jul+aug= 31*3-30=63... (jul+aug+sep)/3=30 => sep = 30*3 - (jul+aug) = 90-63=27

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jitendra hada  (8 years ago)

27 is correct answer

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RAMADOSS  (8 years ago)

c.27
June+July+Aug=93
June =30
July+Aug=63
July+Aug+Sep=90
Sep=27

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MANIKANDAN  (8 years ago)

June + July + August = 31*3 = 93 -----------( 1 )
July + August + September = 30*3= 90 --------------(2)
june = 30

Now eqvate equ 1 and 2 we get
June - Sep = 3 -----------------( 3 )

Then substitute the value of June=30
In the equ (3)
Now we get Sep = 27


Ans is 27

Is this solution Helpfull? Yes (1) | No   

shagufta  (8 years ago)

total temp. of (june+july+aug)=3*31
=93
total temp. of (july+aug+sept) = 3*30
hence, temp of sept. 30-3= 27

Is this solution Helpfull? Yes (1) | No   

priyanka jaiswal  (8 years ago)

27
93=june+ju+au
90=July+au+se
ju+au=63 then
sep=90-63=27

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Sanket  (8 years ago)

C.27 is answer

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chandresh  (8 years ago)

(30+JA)/3 = 31
JA =63

so,
(63+sep)/3 = 30
sep = 27

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Shubham sahu  (6 years ago)

june ,july,august =93
july,august,sep=90
so july+august=63 and sep= 90-63=27

Is this solution Helpfull? Yes (1) | No (1)  

Avishek Singh  (4 years ago)

(june+july+aug)/3=31-----------(1)
(july+Aug+Sep)/3=30------------(2)

sub equation (2) from equation (1),
we get,
June - Sep=3 --------(3)
given, june=30.
put the value in equation 3
we get,
sep=27.(Ans)

Is this solution Helpfull? Yes (1) | No   

Ann Tressa Pilson  (4 years ago)

june + july+ august=(3*31)=93.....(1)
given, july + august +sep=(30*3)=90....(2)
as per avg=sum/no:of
i.e,
eq(1)
30+(july+aug)=93
july+aug=93-30=63
in equ(2)
63+sep=90
sep=90-63=27

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