Latest TCS Aptitude Question SOLUTION: If 28a+30b+31c = 365 then value of a+b+c = ? 1. 11 2. <11 3. >13 4. 12

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(#M40153794) TCS Logical Reasoning question Keep an EYE

If 28a+30b+31c = 365 then value of a+b+c = ?
1. 11
2. <11
3. >13
4. 12

Asked In TCS AKSHAY (8 years ago)

Unsolved Read Solution (16)

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Read Solution (16) :

jonaki  (8 years ago)

As feb -> 28 days so 1 month.

jan,march,may,july,aug,oct,dec-> 31 days..so..7 months

apr,jun,sep,nov->30 days... so.. 4 months

a=1
b=7
c=4

a+b+c=12

Is this solution Helpfull? Yes (23) | No (1)  

DIVYA GAUR  (8 years ago)

its 12
coz feb has 28 days
4 months have 30 days
nd 7 have 31 days
so
28*1+30*4+31*7=365
where 365 is num of days in year
so a+b+c=12

Is this solution Helpfull? Yes (4) | No   

Jagadeesh   (8 years ago)

In the above question we can consider that the variables a,b,c as no. of days of a month. So in a year no. of months containing 28 days =1 ie a=1,similarly b=4,c=7 .therefore a+b+c=1+4+7=12

Is this solution Helpfull? Yes (3) | No   

Venkateswarlu  (8 years ago)

28, 30,31 are the total days in a month.
365 is the total days in a year.
then, a+b+c is the total months in a year =12

Is this solution Helpfull? Yes (1) | No   

juhi  (8 years ago)

28 is the no. of days in february . therefor a = 1
30 is the no. of days of 4 months i.e(april, june, sept , nov) b=4
31 is the no. of days of 7 months .i.e( jan,march,may,july,august,oct.,dec) c= 7

so, A+B+C= 1+4+7= 12 ans.

Is this solution Helpfull? Yes (1) | No   

shagufta  (8 years ago)

As here given that total sum is 365. also ,we know that in 1 year total no of days =365
so,
feb=28
30 days=april,june,sept,nov , 4 months
31 days=jan, march, may,july, aug, oct, dec. 7 months
hence, a+b+c=1+4+7
=12

Is this solution Helpfull? Yes (1) | No   

kailash bajya  (8 years ago)

here February had 28 days..
so... 30 day *4
and 31 *7
so we have total 12 months and in which 4 month had 30 day and 7 month have 31 days
and. is 12.

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sri pallavi chittimalla  (8 years ago)

option-4
Number of months having 28 days = 1
Number of months having 30 days = 4
Number of months having 31 days = 7
28 x 1 + 30 x 4 + 31 x 7 = 365
Here, a = 1, b = 4, c = 7.

a+b+c = 12

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Ancy  (8 years ago)

12
365 days=12months

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lakshmi  (8 years ago)

answer is 12. we have to consider this as month and year....... 365 is an ordinary year. there are 28 days in feb. so 2+4+6=12

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chanchal yadav  (8 years ago)

12..................

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naveenkumar yenda  (8 years ago)

jan,march,may,july,aug,oct,dec-> 31 days..so..7 months

apr,jun,sep,nov->30 days... so.. 4 months
a=1
b=7
c=4
a+b+c=12

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Shubham  (8 years ago)

28a+30b+31c=365 .
it can be written as 28*(a+b+c)+(b+2c)=365
28*13+1=365
or28*12+29=365
as b+2c cannot be equal to 1,therefore (a+b+c)=12,
if we consider a,b,c as '+' integers.

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Saunak Das  (8 years ago)

If we notice this question, we cn understand the logic. There is 365 which is a total year. Now look at d terms 28,30,31. These may be number of days in month.
We have to calculate how many months are there which have 28,30,31 days. So easily we get (28*1)+(30*4)+(31*7)=365. So a+b+c=(1+4+7)=12.

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Vishal Kumar  (8 years ago)

Answer is 4. 12
28*1+30*4+31*7=365,
so a=1,b=4,c=7 => a+b+c=1+4+7=12

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AKASH TOMER  (8 years ago)

a=1,b=5,c=6
a+b+c=11
since it is the format of year given only one month have 28 day ,6 month have 31 day and 5 month have 30 day

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