Latest Infosys Aptitude Question SOLUTION: If Ever + Since = Darwin then D + a + r + w + i + n is ?

Lets number the alphabets as follows
1 2 3 4 5 6 7 8 9 0
A B C D E F G H I J
K L M N O P Q R S T
U V W X Y Z.
From this E+V+E+R=5+2+5+8
S+I+N+C+E=9+9+4+3+5
5258+99435=104693
Here, DARWIN=104693
So,D+A+R+W+I+N=1+0+4+6+9+3=23
23 is the ans

As it’s a sum of 3 numbers hence the maximum value of D could be 2 or 1, but then we look at S which could have maximum value 9 and if it gets a carry of 1 then the value of A will be 0 and the D=1.
2. Then we looks at E and I which results in R, as 9 is already occupied by S so E could be 8 and I could be 7 and R will be 5 with carry 1.
3. Then we place the values of R=5 and E=8 resulting in N=3 with carry 1.
4. In ten’s digits – E=8 and and value of C could be 3,4,6 (As all others are occupied) and To make I=7 (previously assigned in step 2) E must be added by 9 which is already occupied by S. So this hit ends here.
Now start again with reduced value of E or I, repeat above steps until you get a correct answer or a dead end.
5. Repeating above steps one time comes with E=5 and I=7 which results in R=3 carry=1.
6. Placing R=3 and E=5 in unit digits and their sum gives 8.
7. in ten’s digits place E=5 now you can add 2 to make I=7 hence C=2.
8. in 100’s digits you have N=8 (from step 6) and only digits that are left now are 4 and
6 hence. So placing V=4 you will get W=2 which is not true because it is already assigned to C. So we are left with only V=6 as the ultimate choice and this leads the result in to W=4.

Hence this way we got the answer

….5 6 5 3
….E V E R
..9 7 8 2 5
+ S I N C E
———————-
D A R W I N
1 0 3 4 7 8

Hence D+A+R+W+I+N = 1+0+3+4+7+8 =23

HW ITS EVER = 5653???/

ever = 5653
since=97825
--------------------
103478 = darwin
ans= 1+0+3+4+7+8=23

ever+since=darwin
8384+96278=104562
D+a+r+w+i+n=18

how it is possible please explain properly

How can we take same value for different alphabet