Latest Elitmus Aptitude Question SOLUTION: Ram has two dies which has a nos 2,3,4,6 when he throws the two dies together find the no of possibility so that the some of the two dies should be even...???

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(#M40154102) ELITMUS Numerical Ability question probability Keep an EYE

Ram has two dies which has a nos 2,3,4,6 when he throws the two dies together find the no of possibility so that the some of the two dies should be even...???

Asked In Elitmus parul sharma (9 years ago)

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Read Solution (7) :

Deepanshu Gupta  (9 years ago)

total possible combinations=(2,2)(2,4)(2,6)(4,2)(4,4)(4,6)(3,3)(6,2)(6,4)(6,6)=10
so probability=10/16=5/8

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pratibha deshwal  (9 years ago)

total outcome will be 16, and to get even number it should be a combination of (2,2)(2,4)(2,6). and so on
counting to 10
therefore 10/16=5/8

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Atul Ranjan  (9 years ago)

First can have 4 outcomes
Second can also have 4 outcomes
So total combination should be 4×4=16.
Now, even+even=even and odd+odd=even
So 3 even numbers . Outcome of even number one on dice is 3. Same in the second one
So total possible outcome is 3×3=9
Now last digit i.e odd is 3. As combination of 3 can be with 3 only... as odd+odd=even
So finally 9+1=10 is total number of outcome for even.
So it would be 10/16 or 5/8 (possible outcome/total outcome).

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shreya  (9 years ago)

n(e)=(2,2)(2,4)(2,6)(4,2)(4,4)(4,6)(3,3)(6,2)(6,4)(6,6)=10 ,p(e)=16
probability=n(e)/P(e)=10/16=5/8

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shiba  (9 years ago)

We know ,
even+even=even or odd +odd =odd
so out of given numbers(2,3,4,6)...there are only 3 even numbers ..so possibility of getting even number when two dies are thrown is [(2,4) ,(2,6),(4,2) ,(4,6) ,(6,4),(6,2)].....

....so total no of ways to get even number is 6.
and total nof of possible outcome is 4*4=16
so probability of this event is =6/16 i.e 3/8

i hope this answer is helpful

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Arpit dubey  (9 years ago)

5/8 will be the answer apart from the confusion that what no's does the other two #faces posses....

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Satyaki Ghosh  (9 years ago)

answer will be 11/18
bcoz one cube may also show the number, whether other cube may not show any number when rolled

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