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(#M40154171) ITC Numerical Ability question Keep an EYE

How many ways can 1500 be expressed as a product of three numbers

Asked In ITC Sailesh Mishra (9 years ago)

Unsolved Read Solution (5)

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Read Solution (5) :

NIGAM SINGHA  (8 years ago)

HCF OF 1500= 2^2*3*5^3
THEREFORE AS WE KNOW WHEN N=A^P*B^Q*C^R FOR PRODUCT OF 3 NUMBERS
IS EXPRESSED AS 1/2[(P+1)(Q+1)(R+1)]
SO HERE THE ANSWER IS 1/2 *24 = 12

Is this solution Helpfull? Yes (14) | No (8)  

anil  (9 years ago)

7p3=7!/4!=210

Is this solution Helpfull? Yes (7) | No (9)  

ANURADHA MISHRA  (7 years ago)

1500=2*3*5*5*5*2
so by combining
combo1=(2*3)*(5*5)*(5*2)=1500
combo 2=(2*2)*(3*5)*(5*5)
combo3=(5*3)*(5*2)*(5*2)
ans.3

Is this solution Helpfull? Yes (3) | No (2)  

SAIKAT BARMAN  (9 years ago)

1500=25*20*3

Is this solution Helpfull? Yes | No (14)  

Mayank Gupta  (8 years ago)

Express 3240 as a factors of prime nos

3240 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 5 = 23 x 34 x 5

so these 3 nos of 2's can be distributed to 3 integres a,b,c in : [3+(3-1)]C (3-1) ways i.e 5C2 = 10 ways

Nos of ways in which 4 nos of 3's can be distributed to 3 integers : [4+(3-1)]C (3-1) ways i.e 6C2 = 15 ways

Nos of ways in which 1 nos of 5 can be distributed to 3 integers : [1+(3-1)]C (3-1) ways i.e 3C2 = 3 ways

So total ways = 10 x 15 x 3 = 450

Is this solution Helpfull? Yes | No (1)  

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