Latest TCS Aptitude Question SOLUTION: Car A leaves city C at 5pm and is driven at a speed of 40kmph. 2 hours later another car B leaves city C and is driven in the same direction as car A. In how much time will car B

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Time Distance and Speed

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40154335) TCS Numerical Ability question Keep an EYE

Car A leaves city C at 5pm and is driven at a speed of 40kmph. 2 hours later another car B leaves city C and is driven in the same direction as car A. In how much time will car B be 9 kms ahead of car A if the speed of car is 60kmph

Asked In TCS Sneha Singh (8 years ago)

Unsolved Read Solution (14)

Is this Puzzle helpful?   (14)   (4) Submit Your Solution Time Distance and Speed

Read Solution (14) :

raviranjan  (8 years ago)

after 2 hours
Car A has distance from city C=2*40=80
hence,Relative speed=60-40=20kmph
time taken to B to goes 9 kms ahead from Car A=(80+9)/20=4.45hours
hence Actual time=5+4.45(4 hours And 27 minutes)=9:27 P.M

Is this solution Helpfull? Yes (18) | No (3)  

Soumen Maity  (8 years ago)

Let the time is T.
60T= 40(T+2)+9
T=4hrs 27mins

Is this solution Helpfull? Yes (10) | No (1)  

Pradeep Jagannath Rathod  (8 years ago)

Nobody added that 2 hour later stmt...so the ans is 9:27+2h == 11:27pm

Is this solution Helpfull? Yes (7) | No (2)  

DINESH KUMAR DWIVEDI  (8 years ago)

after 6 hrs both cars A and B be at the same place which is 240 km from the city C.for car A-since in 60 min car A travels 40 km,therefore in 1 min car A travels 2/3=0.67km.
for carB-since in 60 min car B travels 60 km,therefore in 1 min carB travels 1 km.
now after applying hit and trial-after 27 min the difference in distance of both the car be 9 kms.
hence,after 6.27hrs car B will be 9 kms ahead of car A.

Is this solution Helpfull? Yes (2) | No (3)  

ashish sahu  (8 years ago)

B leaves at 7 pm so it will be 9km ahed after 11:27

Is this solution Helpfull? Yes (2) | No   

manish kumar  (8 years ago)

at 9:27 pm,at 9:00pm both will be at same pt. after that relative velocity of car B against A is 20kmph.so,time=(9/20)*60 minutes.so ,the ans is 9:27pm.

Is this solution Helpfull? Yes (1) | No (2)  

sagar kumar  (8 years ago)

in 2 hr A will travell =80km,
let x be the time take by b to be 9 km ahead of a
a/q
80km+9km+40x=60x
89/20 hr=4 hr 9/20*60=4hr 27 min
ans will 7pm+4.27min=11.27min

Is this solution Helpfull? Yes (1) | No   

denil chawda  (8 years ago)

4.495 hrs

Is this solution Helpfull? Yes | No (2)  

akchat   (8 years ago)

4 hrs and 27 minutes

Is this solution Helpfull? Yes | No (2)  

arunabh  (8 years ago)

something 4.30 min approx

Is this solution Helpfull? Yes | No (2)  

siva krishna somisetty  (8 years ago)

Car A -- 5pm -> 0kms
Car A --- 11:30 pm -> 260kms

car B -- 7pm -> 0kms
car B -- 11:30pm -> 270kms

so, approx.. 4.45 hrs later Car B should be 9kms ahead :)

Is this solution Helpfull? Yes | No (1)  

aditi ojha  (8 years ago)

A= distance D, speed 40 n time T
B= distance D+9, speed 60 n time T-2
solving this we get T=6.45
thus time taken by B=4.45

Is this solution Helpfull? Yes | No (2)  

aryan raj  (4 years ago)

The distance covered by a in 2 hrs is :

40 × 2 = 80km

Let the distance to be covered by a at the time b catches up with a be x.

They take the same time to reach the meeting point.

b covers 80 + x

Time taken by a is :

x/40

Time taken by b is :

(x + 80) / 60

x /40 = (x + 80) / 60

60x = 40(x + 80)

60x = 40x + 3200

60x - 40x = 3200

20x = 3200

x = 3200/20

x = 160

The time taken for them to catch up is :

160/40 = 4hrs

The relative distance is 9 km

Relative speed is :

60 - 40 = 20km/h

Time = 9/20 hrs

9/20 × 60 = 27 minutes

The total time is 4hrs + 27mins = 4hrs 27 mins

Is this solution Helpfull? Yes | No   

Sourya Kumar Verma  (3 years ago)

At 7PM A's -----> 40 * 2 = 80 Km.
At 7PM B's -----> 0 Km.
Total distance B has to travel to get 9 km ahead ---> 80+9 Km.
relative speed of B w r to A --> (60 - 40) km/hr.
Total time taken by B to get 9 km ahead ---> 89/20 hr; or 4 hr 27 min.
since B started at 7 PM so at 7:00 + 4:27 = 11:27 PM will be 9 Km ahead of A

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.