Latest Elitmus Aptitude Question SOLUTION: i wrote exam 22 nov 2015. In that these questions were repeated from verbal 1.I bought three different pencils. Haven't you seen ---------- of them (a)either (b) all (c)any

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(#M40154751) ELITMUS Category question 22 Nov 2015 Keep an EYE

i wrote exam 22 nov 2015. In that these questions were repeated

from verbal

1.I bought three different pencils. Haven't you seen ---------- of them

(a)either (b) all (c)any (d)i didn't remember the option

answer is (c)any


2. I saw _______ flowers in the garden, but i forget to take camera with me.

(a)many (b)all (c)no of (d)not remember

answer is (a) many

from data sufficiency

1. rope is cut into 4 part and one part is of 3cm , then what is the size of smallest part
a) sum of large three part =11cm
b) sum of short three part =10 cm

from quant

1.How many number of numbers are possible which are greater than10 and less than 1000 in which digit is greater than its left digit? Eg 12,23....but not 11.
1)100 2)120 3)210 4)240


2.How many ways we can get a number greater than 6*10^6 with digits 5,5,6,6,9,9,0.without repetition?
(a)180 (b)360 (c)540 (d)720

answer is 720

Asked In Elitmus Umabandekar (8 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

vivek  (8 years ago)

any
many
120
360

Is this solution Helpfull? Yes (10) | No   

Abhishek  (8 years ago)

there is 7 numbers 5,5,9,9,6,6,5,0
and the number which is going to generate must be greater than 60,00,000 as per the above questions.
now draw 7 space just like this : _,_,_,_,_,_,_ we can not put 0 or 5,5 as first digit. because it will be less than 60,00,000 so there is only 4 numbers that may have first place i.e (9,9,6,6) now the next digit could be anything from the set except the first digit
so 4*6*5*4*3*2*1/2*2*2 =360 . we have 2 fives 2 nines 2 sixes that why I divided the equation

Is this solution Helpfull? Yes (10) | No (1)  

aman kumar  (8 years ago)

For data sufficiency
D)both are insufficient to ans the question

Is this solution Helpfull? Yes (2) | No   

ANKUSH SAXEN  (8 years ago)

for data suffcncy both stmnts r requires
4+4+3=11
4+3+3=10

Is this solution Helpfull? Yes (1) | No (4)  

ABHISHEK SHARMA  (8 years ago)

ans is 180
(2*6*5*4*3*2*1)/2!*2!*2!

Is this solution Helpfull? Yes | No (5)  

Deepak kumar singh  (8 years ago)

Abhishek but 5 is three tym

Is this solution Helpfull? Yes | No   

dipikabhagat  (8 years ago)

540 ways
Total 7 digits no - nos starting with 0

=7!/(2!*2!*2!)- 6!/(2!*2!*2!)

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