Latest TCS Aptitude Question SOLUTION: I just finished 3 marble games & have 21 marbles.In the 1st game I lost half of my marbles.Inthe 2nd game I won 11 times what I had at the end of the 1stgame.In the 3rd game I wo

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I just finished 3 marble games & have 21 marbles.In the 1st game I lost half of my marbles.Inthe 2nd game I won 11 times what I had at the end of the 1stgame.In the 3rd game I won 9 marbles.How many marbles Did I have when I started playing?
a)6 b)4 c)8 d)2

Asked In TCS Rik (8 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

Richa  (8 years ago)

I think ans is 2.let no of marble be x
After 1 game marble =x/2
In 2 game 11*x/2
In third 9
So total he have 21 in end adding all equating
9+11x/2+x/2=42
Ans 2

Is this solution Helpfull? Yes (14) | No (2)  

Shagufa  (8 years ago)

Let initially he has x marble
At the end of 1 game marbel he has=x/2
At end of 2nd game, marble he has=x/2 + 11x/2 = 6x
Afte 3rd game marbel he has= 6x+9
So equating we have
6x+9=21
X=2

Is this solution Helpfull? Yes (8) | No   

keerthana chennamsetty  (8 years ago)

RICHA your answer is correct. but i think equation equating to 42 is not correct.
i think equating the expression to 21 will give the answer as 2.

Is this solution Helpfull? Yes (3) | No   

svs.pradeep  (8 years ago)

d,assume intially x then half of it and multiplied 11 times and add 9 to it

Is this solution Helpfull? Yes (1) | No   

Anika  (8 years ago)

@ Richa
Pls tell Why equating the equation to 42?
What is the reason of 42?

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papolu  (8 years ago)

from the options we can verify easily.....
2/2=1.............................................. lost half of his marbles
1+(1*11)=12................................... won 11times what he had in 1st game
12+9=21............................................. won 9 marbles more

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Abhishek nkumar  (8 years ago)

Answer is option (d) - 2.
let initially I have 2 marbles then,
after 1st game - 1 is remaining
after 2nd game- 1+11*1=12 total
after 3rd game- 12+9 = 21 total is remaining which is equal to 21 marbles as per question...hope it is easy to get

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Richa  (8 years ago)

Guys it was 21 only by mistake I write it 42

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vivek kumar  (8 years ago)

let there be x marble initially after 1st game he left with x/2
in second game he wn 11time so ans be x2+11*x/2=6x
in third game he won 9 marbel so 6x+9=21=2 ans

Is this solution Helpfull? Yes | No (1)  

Prashanti  (8 years ago)

Let x be the initial ni of marbles. In 1st game he lost half, so he has x/2 with him. In the second game he won 11 times of what he had in 1st ,I.e. 11x/2, in 3rd he win 9. So eq will be (x/2)+(11x/2)+9=21.
So ans is 2

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