Latest Elitmus Aptitude Question SOLUTION: if 1/a + 1/b + 1/c = 1/(a+b+c) where a+b+c !=(not equals) 0, abc != 0 , then what is the value of (a+b) (b+c) (c+a)? a)equal to 0 b) greater than 0 c) less than 0 d) can't dete

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(#M40155157) ELITMUS Numerical Ability question Elitmus Question Keep an EYE

if 1/a + 1/b + 1/c = 1/(a+b+c) where a+b+c !=(not equals) 0, abc != 0 , then what is the value of (a+b) (b+c) (c+a)?
a)equal to 0
b) greater than 0
c) less than 0
d) can't determine

Asked In Elitmus Jagadeesh Ginjupalli (8 years ago)

Unsolved Read Solution (8)

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Ravi kumar  (8 years ago)

1/a + 1/b + 1/c =1/ (a+b+c)
=> 1/a + 1/b =1/ (a+b+c) - 1/c
=> (b+a)/ab = (c - (a+b+c)) / c(a+b+c)

Cross multiplying (Since, a,b,c !=0 and a+b+c != 0)

=> c(a+b+c)(b+a) = - ab(a+b)
=> (a+b)( ca +cb +cc + ab ) = 0
=> (a+b)( ca + cc + cb + ab) = 0
=> (a+b)(b+c)(c+a)=0

Is this solution Helpfull? Yes (4) | No (3)  

Paplesh k. gour  (8 years ago)

Taking 11 common from LHS separating z and breaking 151001 as a factor of 11 with some remainder in RHS
11(113v+112w+11x+y) + z = 11x13727 + 4 [hence; z = 4]
Equating z =4 and cancelling 11 from each side we get the following simplified equation and again repeating the above procedure;
11(112v + 11w +x) + y =11x1247 + 10 [y = 10]
11(11v + w ) + x = 11x113 + 4 [x = 4]
11v + w = 11x10 + 3 [v=10 , w=3]
So we get the unique solution for the above equaton.

Is this solution Helpfull? Yes (2) | No (1)  

Paplesh k. gour  (8 years ago)

Sorry this solution for above question.

Is this solution Helpfull? Yes (2) | No   

ANKUSH SAXEN  (8 years ago)

ans is equal to 0
let a=-1,b=1,c=2
1/-1+1/1+1/2=1/(-1+1+2)
we get 1/2=1/2 condition satifies

Is this solution Helpfull? Yes (2) | No (4)  

Lavanya  (8 years ago)

ab+bc+ba/abc=1/(a+b+c)
=> (ab+bc+ca)(a+b+c)=abc
=> a^2b+ab^2+abc+abc+b^2a+bc^2+abc+a^2c+ac^2=abc
=> a^2b+ab^2+bc^2+b^2a+a^2c+ac^2+2abc=0
=>(a+b)(b+c)(c+a)=0

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dhwani sondhi  (8 years ago)

a) equals to 0
equates both equations...we get 0

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priyanka  (8 years ago)

I got answer as (-a(c^2))

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RASHMI KIRAN VERMA  (8 years ago)

equal to 0

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