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(#M40155580) TCS Numerical Ability question Keep an EYE

when 3 dice are rolled find the probability of getting a sum of 13?

Asked In TCS pavithra venkatesan (9 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

Piyalichatterjee  (9 years ago)

14. There are 2 groups named brown and red. They can n't marry in the same group. If the husband or wife dies then the person will revert to their own group. If a person is married then the husband will have to change his group to his wife's group. Children will own the mother's group. If man is red then his mother's brother belong to which group if he is married
a. red
b. brown
c. red and brown
d. none

Is this solution Helpfull? Yes (24) | No (1)  

sandeep sahu  (9 years ago)

x+y+z=13 => x+y=13-z
for z=1 x,y (6,6)
z=2 (5,6)(6,5)
z=3 (6,4)(4,6)(5,5)
similarly z=6 have 6 pair
so 1+2+3+4+5+6=21
total=6x6x6=216
ans=21/216=7/72

Is this solution Helpfull? Yes (19) | No   

Vignesh S  (9 years ago)

Total Space6^3=216
Possible Ways
1 6 6 3i/2i =3+
2 5 6 3i=6+
3 4 6 3i=6 +
3 5 5 3i/2i=3+
4 4 5 3i/2i=3
===21 possible ways

21/216 Is answer

Is this solution Helpfull? Yes (13) | No   

Deepika Jain  (9 years ago)

@piyali
correction in the ans it would be brown as mother would be red and than her married brother would be in another group i.eof brown

Is this solution Helpfull? Yes (5) | No (1)  

niki goyal  (9 years ago)

answer is 21/216
as there are 6 dices rolling together 6^3=216 which is total probability
now for the case getting sum =13
we can fix one dice and roll othr two dice
like taking 1st dice outcome as 1 so we need 12 as sum from othr two dice so the probable cases would be:
1,6,6
similarly taking 1st dice to be 2, we get:
2,6,5
2,5,6
3,5,5
3,4,6
3,6,4
4,4,5
4,5,4
4,6,3
4,3,6
5,5,3
5,3,5
5,6,2
5,2,6
5,4,4
6,1,6
6,2,5
6,3,4
6,4,3
6,5,2
6,6,1
so total cases are 21
thus ans is 21/216

Is this solution Helpfull? Yes (5) | No   

KokilA  (9 years ago)

FOR 3 DICE
SUM=13
PROBABILITY=21/216

Is this solution Helpfull? Yes (1) | No (1)  

p  (9 years ago)

7/72
total sample spaces=6^3=216
probability=6+5+4+3+2+1/216=7/72

Is this solution Helpfull? Yes | No (3)  

Rupesh Kumar  (9 years ago)

Answer is 21.

Use formula
suppose k is the sum of three dices we want
then for 3

Is this solution Helpfull? Yes | No (2)  

Rupesh Kumar  (9 years ago)

Answer is 21/216 or 7/72
Use formula
suppose k is the sum of three dices we want
then for 3

Is this solution Helpfull? Yes | No (1)  

R.Mounika  (8 years ago)

1/36
n(s)=216
n(E)=6
p(E)=6/216=1/36

Is this solution Helpfull? Yes | No (1)  

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