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(#M40155812) TECH MAHINDRA Numerical Ability question Numerical Ability Keep an EYE

What was the day of the week on December 26,1995?

a) Friday
b) Tuesday
c) Sunday
d) Monday
e) None of the above Ans

Asked In Tech Mahindra Aashu (8 years ago)

Unsolved Read Solution (4)

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Read Solution (4) :

manasa  (8 years ago)

ans -b
tuesday

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Bodapati Ramya  (8 years ago)

126 dec, 1995 = (1994 years + Period from 1.1.1995 to 26.12.1995)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) -14= 1

94 years has 23 leap years + 71 ordinary years.

Number of odd days in 97 years ( 23 x 2 + 71*1) = 118 = 5days

1.1.1995-26.12.1995=365-26=239 days
239 days = 1 odd day.

Total number of odd days = (0 + 1 + 5+1+2+ 0) = 9 days=2 odd days

Given day is Wednesday.

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Vishal Kumar Saw  (8 years ago)

Tuesday
26 December 1995

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janardhana reddy  (8 years ago)

b)Tuesday
Explaination:
month code month wise: 0 3 3 6 1 4 6 2 5 0 3 5
year code: 2 0 6 4
2=1800-1899,0=1900-1999, 6=2000-2099,4=2100-2199.
now procedure:
consider the given that:26-12-1995.
Step1: 26+95 =121(date + Last two Digits of year)
step2: 95/4 = 3(coefficient)
step3: month code = 5
step4: year code = 0
add all these----------------------
7)149(21 [in the last step consider remainder Only]
14
--------
09
7
------------
2 Consider the remainder here
here Sunday--0,monday---1,tuesday----2 etc
You will get the answer.

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