Latest Capgemini Aptitude Question SOLUTION: In a system of coding ACCESS is coded CEEGUU, PONTIFF as HHKPORV, LIMERICK as EGKKMNOT and LAMINATE as CCGKNOPV. what is likely to be the word of Which the code is COTUV? a)TRAPS

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(#M40156001) CAPGEMINI Logical Reasoning question Coding Keep an EYE

In a system of coding ACCESS is coded CEEGUU, PONTIFF as HHKPORV, LIMERICK as EGKKMNOT and LAMINATE as CCGKNOPV. what is likely to be the word of Which the code is COTUV?
a)TRAPS b)PARTS
c)SMART d) none of these

Asked In Capgemini Anjan (8 years ago)

Unsolved Read Solution (5)

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Read Solution (5) :

Alok  (8 years ago)

ACCESS => CEEGUU
POINTFF => HHKPQRV
LIMERICK => EGKKMNOT
LAMINATE => CCGKNOPV
AMRST ==> COTUV

Every letter of the word is added by 2 then we get the code word in which the letters are jumbled except in the first word ACCESS which is to confused u.

So the correct answer is option C) SMART

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Janaki  (8 years ago)

In this question...
The above codes are decoded as.. arranging the alphabets from A and then add+2
1. A C C E S S

these codes are already arranged in alphaetical order so it doesnt matter to reaarrange in alphabetical order. simply add + 2 to them.

A +2=C
C+2=E
C+2=E
E+2=G
S+2=U
S+2=U

SIMILARLY,
2.PONTIFF

ARRANGE IN ALPHABETICAL ORDER

FFINOPT THEN ADD +2

SIMILARLY,
3.LIMERICK
ARRANGE IN ALPHABETICAL ORDER
CEIIKLMR

SIMILARLY,
4.LAMINATE
ARRANGE IN ALPHABETICAL ORDER
AAEILMNT

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Shubham  (8 years ago)

Though the question seems too tricky and i can't ensure you of the correctness of my answer. But what I tried is that I am posting here.

As we Know A=1, B=2, C=3........Z=26

A C C E S S ----> C E E G G U
In the above case all the letters are changed as A+2 = C, C+2=E....

P O N T I F F -----> H H K P O R V
In this, the letters are first coverted as
F F I T N O P....
Then see....F+2 = H, K+2 = N.....

L I M E R I C K -----> E G K K M N O T
the confusion comes in this and the later one.
Here, What I did ,
I took E G K K M N O T
and then subtracted 2 from all...
E - 2 = C
G - 2 = E
K - 2 = I
K - 2 = I
M - 2 = K
N - 2 = L
O - 2 = M
T - 2 = R
It means E G K K M N O T ------> C E I I K L M R
If you see above, all these formulated letters are present in L I M E R I C K.

Similarly,
C C G K N O P V -----> A A E I L M N T
All the above letters are present in L A M I N A T E.

Thus, C O T U V will be converted by adding 2 in each.
Therefore we get E Q V W X which is not in the options. hence, none of these

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Avinash Nishad  (8 years ago)

for specific letter constant inc/dec:
for
A-->+2=C
C-->+2=E
.
.
.
SO on
directly for COTUV ---> Decoding start with C-->+2=E, which is not present in options....so none of this

Is this solution Helpfull? Yes (2) | No (9)  

vasudev  (8 years ago)

SMART is the answer..
Consider CEEGUU ..If we substract 2 from each letter we get ACCESS.. For example For 'C' If we substract 2 we get 'A'.. Similarly for 'E' we get 'C'
Similarly for COTUV we get AMRST
And if we jumble it ..we get SMART..
Same apllies for 2nd,3rd, and 4th Cases

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