Latest CTS Aptitude Question SOLUTION: Two equal amounts are deposited in two bank at same interest rate 12% p.a. for 7 years and 4.5 years respectively. If the different between the interest is Rs. 585 then what was ea

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(#M40156411) CTS Numerical Ability question Keep an EYE

Two equal amounts are deposited in two bank at same interest rate 12% p.a. for 7 years and 4.5 years respectively. If the different between the interest is Rs. 585 then what was each amount?

1) Rs. 1650
2) Rs. 1750
3) Rs. 1850
4) Rs. 1950
5) Rs. 2050

Asked In CTS ABHINAV PUSHPAM (8 years ago)

Unsolved Read Solution (9)

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Read Solution (9) :

afsheen  (7 years ago)

According to the question Sum ,P is same R= 12% in both case

Then Interest of Rs.585 will be the interest of the difference of time period= (7-4.5)= 2.5 years

Now, P = 100 x SI/R*T = 100×585/12×2.5

P = 100×585/30 = 1950

Is this solution Helpfull? Yes (12) | No   

prathyusha  (8 years ago)

4)Rs. 1950

Is this solution Helpfull? Yes (3) | No (5)  

Keerthana T  (7 years ago)

let x be the principle amount.

(x*7*12)/100 - (x*4.5*12)/100=585

therefore,x=1950

Is this solution Helpfull? Yes (1) | No   

Pallab Kumar Ray  (7 years ago)

Acc to question Sum ,P is same R= 12% in both case

Then Interest of Rs.585 will be the interest of the difference of time period= (7-4.5)= 2.5 years

Now, P = 100xSI/RT = 100×585/12×2.5

P = 100×585//30 = 1950

Is this solution Helpfull? Yes | No (1)  

Prabhat Burnwal  (7 years ago)

585=p*12*7/100 - p*12*4.5/100
solving for p, we get 1950

Is this solution Helpfull? Yes | No   

A.ROSHINI  (7 years ago)

let the amount be'x'.
interest of 12%for 7,4.5 yrs.
(x*12*7)/100*(x*12*4.5)/100=585
ans:1950

Is this solution Helpfull? Yes | No   

alpa sharma  (7 years ago)

option 4 i.e 1950
p*12*7 - p*12*4.5 = 58500
on solving this we get p=1950

Is this solution Helpfull? Yes | No   

Suneena Deen Jacob  (7 years ago)

Here difference of interest=585
N=7 R=12
N2=4.5 R2=12
ie SI1 - SI2=585
SI1=( P * N * R ) / 100
SI2=( P * N2 * R2 ) / 100
SI1 - SI2=( P * N * R ) / 100-( P * N2 * R2 )/100
Taking common term P/100 outside we get
SI1 - SI2=P( N * R - N2 * R2 )/100
585 =P(7 * 12 - 4.5 * 12 ) / 100
=P ( 84 - 54 ) /100
585 * 100 = 30 P
58500 / 30= P
Therefore answer is
Option 4) 1950
585=P/100

Is this solution Helpfull? Yes | No   

Abdul Wadud  (7 years ago)

we know simple interest si=(ptr)/100.
in first case let p=x,t=7 and r=12
in second case p=x and given t=4.5,r=12
so (x*7*12)/100=(x*4.5*12)/100
=>30x=585*100
=>x=1950

Is this solution Helpfull? Yes | No (1)  

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