Latest pratian technologies Aptitude Question SOLUTION: write a programming logic to generate to the series: 1,1,2,12,14,26,40,264,304,568...

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(#M40157004) PRATIAN TECHNOLOGIES Programming question Keep an EYE

write a programming logic to generate to the series: 1,1,2,12,14,26,40,264,304,568...

Asked In pratian technologies Ankit Kumar Gupta (7 years ago)

Unsolved Read Solution (33)

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Read Solution (33) :

Pavani  (7 years ago)

import java.util.Scanner;
class test{
public static void main(String[] ards){
int a = 1;
int b = 1;
Scanner sc = new Scanner(System.in);
System.out.println("Enter the limit of the sequence:");
int n = sc.nextInt();
int c=1;
for(int i = 0; i < n; i++){
if(i < 2)
System.out.println(a);
else
{
c = a +b;
if((i+1)%4 == 0)
c *= 4;
System.out.println(c);
a = b;
b = c;
}

}
}
}

Is this solution Helpfull? Yes (53) | No   

arvind  (7 years ago)

first find the series.. which is a bit confusing.
The series comes like this " 1,1,2,12,14.. " where 1+1=2 =>i+j=2 where i and j are initialized as 1 and the result in a separate variable. in a similar way we need to consider to add the "j" values and the "ans" values so as to get the next number of the series. Once we get an answer which is a factor of 3, We need to multiply the result by 4.

1
1
(1+1)=2 ////
(1+2)=3 // (which is a modulus of 3)// hence multiply by 4. which is equal to= 3*4=12 which is the fourth number of the series. => ans = 12
Now, j=2, ans= 12.
(2+12)=14 // (j=12, ans= 14)// now add both for next number of the series
(12+14)= 26 // (6th number in series)
(14+26)= 40
(26+40)= 66 => which is a factor of 3, so multiply by 4 => 4*66 =264= ans
(40+264) => 304.. and goes on


The code logic goes here

{
print ("Hello ");

int i=1,j=1,ans=1;
print (i);
for(int k=0;k

Is this solution Helpfull? Yes (49) | No (6)  

VARSHINI  (7 years ago)

#include
#include
void main()
{
int a=1,b=1,c,i,n;

printf("enter n value ");
scanf("%d",&n);


for(i=0;i

Is this solution Helpfull? Yes (12) | No (5)  

Akshay kumar Gupta  (7 years ago)

a=1;
b=1;
for(int i=3;i

Is this solution Helpfull? Yes (11) | No (11)  

Naveen Mathew  (7 years ago)

class Series{
public static void main(String[] ards){
int a = 1;
int b = 1;
int c=1,n=10;
for(int i = 1; i < n; i++){
if(i < 2)
System.out.print(i+" "+b);
else
{
c = a +b;
if((i+1)%4 == 0)
c *= 4;
System.out.print(" "+c);
a = b;
b = c;
}

}
}
}

Is this solution Helpfull? Yes (10) | No   

E Chiranjeevi  (7 years ago)

1+1 = 2
(1+2)*4 =12
2+12 = 14
12+14 = 26
14+26= 40
(26+40)*4= 264
40+264= 304
264+304 = 568
(304+568)*4 = 3488

Is this solution Helpfull? Yes (7) | No (2)  

Prabhu G  (7 years ago)

public static void main(String[] args) {
int i=1,j=1,k=0;
System.out.println(i);
while(i

Is this solution Helpfull? Yes (6) | No (9)  

MUHAMMED SHIYAS  (7 years ago)

public class Shiyas{

public static void main(String args[])
{
int n1=1,n2=1,n3,i,count=10,c=3,a=4;
System.out.print(n1+" "+n2);//printing 0 and 1

for(i=2;i

Is this solution Helpfull? Yes (5) | No (1)  

Sushree Manisha Sahoo  (7 years ago)

import java.util.Scanner;

public class Series {
public static void main(String[] args) {
Scanner scn = new Scanner(System.in);
System.out.println("Enter range");
int n = scn.nextInt();
int a = 1;
int b = 2;
int c;
System.out.print(a+" "+a+" "+b+" " );
for(int i = 3;i

Is this solution Helpfull? Yes (5) | No (1)  

Prathap   (6 years ago)

//
int main() {
// 1,1,2,12,14,26,40,264,304,568...
int x=1;
int y=1;
int n=500;
int z;
printf("%d %d t",x,y);
while(n>z){
z=x+y;
if(z%3==0) z=z*4;
printf("%d t", z);
x=y;
y=z;
}
}

Is this solution Helpfull? Yes (5) | No   

vivek sharma  (6 years ago)

series is like-1,1,2,12,14,40,l264,304,568.............






#include
#include
void series(int,int);
int main()
{

int a=1;
int b=1;
int c=0,d=0,n=0;
printf("%dt%dt",a,b);
series(1,1);

return 0;
}

void series(a,b)
{

while(b

Is this solution Helpfull? Yes (4) | No (6)  

Mithilesh kumar choubey  (7 years ago)

class Aaaa
{
public static void main(String[] args)
{
System.out.println("Hello ");

int i=1,j=1,don=1;
System.out.println(i);
for(int k=0;k

Is this solution Helpfull? Yes (2) | No (1)  

anjali  (7 years ago)

872
8+4=2 -> 1 is carry
6+1 carry=7
5+3=8
total ans=872

Is this solution Helpfull? Yes (2) | No   

yatin arora  (6 years ago)

import java.io.*;
import java.math.*;
import java.util.Arrays;

class SeriesYatin {
public static void main(String args[])
{
int a[]= new int[20];
a[0]=1;
a[1]=1;
int k=1;
for(int i =2;i

Is this solution Helpfull? Yes (2) | No   

Kranthi  (7 years ago)

void main()
{
int n,i,s=0;
scanf("%d",&n);
for(i=0;i

Is this solution Helpfull? Yes (1) | No   

pankaj  (6 years ago)

import java.util.Scanner;
public class prg2
{
static Boolean prime(int p)
{
for(int i=2; i

Is this solution Helpfull? Yes (1) | No (1)  

Rajat Sahu  (6 years ago)

# Pratian technology interview question
# write code for given series
# 1,1,2,12,14,26,40,264,304

"""
Series logic
initialise i=j=1
iterate and add i,j
in case j is divisible by 3 , multiple j by 4
thus
1
1
1+1=2
1+2=3 // so multiply 4
j=3*4=12
2+12=14
12+14=26
14+26=40
26+40=66 // so multiply 4
j=66*4=264
40+264=304
.....
"""
# code starts

def series(times):
if times==0:
print("No series")
elif times==1:
print("1")
else:
print("1")
print("1")
i=j=1
for c in range(times-2):
temp=i+j
if temp%3==0:
temp=4*temp
i=j
j=temp
# print j
print(j)

times=int(input())
series(times)

Is this solution Helpfull? Yes (1) | No   

andhi  (6 years ago)

public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner sc = new Scanner(System.in);
int num = sc.nextInt();
int a[] = new int[num];
for (int i=0;i1){
a[i] = a[i-1]+a[i-2];
//System.out.println((i+1)+" "+a[i]);
}
else {
a[i]=1;
//System.out.println((i+1)+" "+a[i]);
}
}
for (int arr : a){
System.out.print(arr+",");
}
}

Is this solution Helpfull? Yes (1) | No   

vamshiteja nizam  (6 years ago)

public class MyClass {
public static void main(String args[]) {
int a=1,b=1;
int d=0;
System.out.print(a+","+b+",");
for(int i=1;i

Is this solution Helpfull? Yes (1) | No   

Prince Pandey  (7 years ago)

/* Write a program to print following Sequence.
1,1,2,12,14,26,40,264,,304,568...
*/

import java.util.Scanner;
class Series1{
public static void main(String[] args){
Scanner scan = new Scanner(System.in);
System.out.println("Enter last number of sequence:");
int n = scan.nextInt();
int first= 1, second= 1, result= 0;
for(int i=1; i

Is this solution Helpfull? Yes | No (2)  

srirama krishna  (6 years ago)

class test{
public static void main(String[] ards){
int a = 1;
int b = 1;
Scanner sc = new Scanner(System.in);
System.out.println("Enter the limit of the sequence:");
int n = sc.nextInt();
int c=1;
for(int i = 0; i < n; i++){
if(i < 2)
System.out.println(a);
else
{
c = a +b;
if((i+1)%4 == 0)
c *= 4;
System.out.println(c);
a=b;
b=c;
}
}
}
}

Is this solution Helpfull? Yes | No (1)  

Prashant kumar singh  (6 years ago)

/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
package hello;
import java.util.*;
import java.util.Scanner;
public class series {
public static void main(String[] args) {
int a=1;
int b=1;
int c;
System.out.print(a+","+b+",");
c=a+b;
for(int i=2;i

Is this solution Helpfull? Yes | No   

pradeep  (6 years ago)

872
it is firstly digit mix with numbers then add previous again add previous and again add previous.

Is this solution Helpfull? Yes | No   

Pratyush Paliwal  (6 years ago)

import java.util.Scanner;
public class Pratian1 {
public static void main(String[] args) {
int i,a,b,c,n;
System.out.println("no of elements in series to be printed");
Scanner scan=new Scanner(System.in);
n = scan.nextInt();
a=1;
scan.close();
a=1;
b=0;
for(i=0;i

Is this solution Helpfull? Yes | No   

priyanka rath  (6 years ago)

import java.util.Scanner;
class Series{
public static void main(String args[])
{
int n=10;
int a[]={1,1};
for(int i=0;i

Is this solution Helpfull? Yes | No   

Ganga  (6 years ago)

class Test1{
public static void main(String args[]){

int start = 1;
int next = 1;
int n;


for(int i=1; i

Is this solution Helpfull? Yes | No (1)  

Abhishek kumar  (6 years ago)

#include
#include
#include
void main()
{
int n;
printf("enter the numbern");
scanf("%d",&n);
int n1=1;
int n2=1;
int i;
int next;
int next1;
int next2;
int next3;
int next4;
int next5;
for(i=0;i

Is this solution Helpfull? Yes | No (1)  

VASU R  (6 years ago)

a = 1;
b = 1;

n=int(input("Enter the limit of the sequence:"));
c=1;
for i in range(0,n):
if i < 2:
print(a)
else:
c = a +b;
if(i+1)%4 == 0:
c *= 4;
print(c);
a = b;
b = c;

Is this solution Helpfull? Yes | No   

syeednihal  (6 years ago)

if((i+1)%4 == 0) I dint get through this step...plz anyone help me

Is this solution Helpfull? Yes | No   

  (5 years ago)

package javasorting;
import java.util.Scanner;


public class SpecialSeries2 {
public static void main(String[] args) {
double a=1;
Scanner kb= new Scanner(System.in);
System.out.println("Enter size of a series");
int sizeOfSeries =kb.nextInt();
System.out.print((int)a+" ");
int count=1;
for(int i=1;i

Is this solution Helpfull? Yes | No   

  (5 years ago)

#include
main()
{
int i=1,n,j=1,res,ans;
printf("nEnter number of terms:");
scanf("%d",&n);
res=i+j;
printf("%dt%dt%dt",i,j,res);
for(i=1;i

Is this solution Helpfull? Yes | No (1)  

Arnab Datta  (5 years ago)

#include
int main()
{
int i,j,t1=1,t2=1,t3,n;
printf("Enter the number of terms : ");
scanf("%d",&n);
printf("nThe series is : ");
printf("%d %d ",t1,t2);
for(i=3;i

Is this solution Helpfull? Yes | No   

  (4 years ago)

package p2;

import java.util.Scanner;

public class Sequence2 {
public static void main(String[] args) {
Scanner scan=new Scanner(System.in);
int n=scan.nextInt();
System.out.print("1"+" ");
System.out.print("1"+" ");
int a,b,c;
a=1;
b=1;
for(int i=1;i

Is this solution Helpfull? Yes | No   

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