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(#M40157090) ELITMUS Numerical Ability question quants Keep an EYE

How many positive number less than 1000 have sum of there digit 17?

Asked In Elitmus SHUBHAM (8 years ago)

Unsolved Read Solution (13)

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Read Solution (13) :

RAIDULSHEKH  (8 years ago)

digits between 1-100 sum 17 =only 2 (89,98)
digits between 101-200 sum 17 =3 (188,179,197)
digits between 201-300 sum 17 = 4 (296,287,278,269)
and so on.....
digits between 301-400 sum 17 =5
digits between 401-500 sum 17 =6
digits between 501-600 sum 17 =7
digits between 601-700 sum 17 =8
digits between 701-800 sum 17 =9
digits between 801-900 sum 17 =10
but in
digits between 901-999 sum 17 =9 (980,971,962,953,944,935,926,917,908)
so total number is
2+3+4+5+6+7+8+9+10+9=63

Is this solution Helpfull? Yes (15) | No (2)  

Anil Pokhariyal  (8 years ago)

I think answer is 75.
digits between 1-100 sum 17 = 2 (89,98)
digits between 101-200 sum 17 =3 (188,179,197)
digits between 201-300 sum 17 = 4
and so on
we have
2+3+4+5+6+7+8+9+10+11=65

I might be wrong. please correct me!

Is this solution Helpfull? Yes (3) | No (1)  

ashish pokhriyal  (8 years ago)

I think answer is 65.
digits between 1-100 sum 17 = 2 (89,98)
digits between 101-200 sum 17 =3 (188,179,197)
digits between 201-300 sum 17 = 4
and so on
we have
2+3+4+5+6+7+8+9+10+11=65

I might be wrong. please correct me!

Is this solution Helpfull? Yes (3) | No (2)  

somanita  (8 years ago)

i think it will be 75.
because 2 digit numbers whose sum is 17 are 89 and 98.
in 3 digit numbers whose sum is 17 starts from (1,8,8) which can be 3 ways
and(1,9,7) in 6 ways.
similarly,(2,8,7),(2,9,6) --------12 numbers can be formed ,
(3,9,5)(3,8,6)(3,7,7)-----------15 numbers can be formed,
(4,9,4),(4,8,5),(4,7,6)---------15 numbers can be formed,
(5,9,3),(5,8,4),(5,7,5),(5,6,6)-----18 numbers can be formed,
(9,8,0),(9,0,8)(8,9,0)(8,0,9)------4 numbers can be formed

Is this solution Helpfull? Yes (2) | No (5)  

Deepak singh  (8 years ago)

Answer will be 65
In my case 1 sorry I say 5 no bw 100 to. 200 ....it will be three only
See My previous answer

Is this solution Helpfull? Yes (2) | No (2)  

ashtosh  (8 years ago)

i guess 64

Is this solution Helpfull? Yes (1) | No (1)  

Anil Pokhariyal  (8 years ago)

I think answer is 75.
digits between 1-100 sum 17 = 2 (89,98)
digits between 101-200 sum 17 =3 (188,179,197)
digits between 201-300 sum 17 = 4
and so on
we have
2+3+4+5+6+7+8+9+10+11=75

I might be wrong. please correct me!

Is this solution Helpfull? Yes (1) | No (6)  

kislaya srivastava  (8 years ago)

In the question it's not mentioned only 3 digit number ,so you have to consider 98 & 89 too. Now,let the three digits are a,b and c . Basically you have to find the number of values of a,b and c,such that a+b+c=17
So there are 19c2 ways, in this we have to subtract the case in which a,b,c can be zero. So, 19c2-(9c2*3)=63
So total numbers less than 1000 having sum of their digits as 17 is 63+2=65. This is a right answer.

Is this solution Helpfull? Yes (1) | No (1)  

abhijeet bunkar  (8 years ago)

my ans is
1330

Is this solution Helpfull? Yes | No (4)  

keerthana  (8 years ago)

i guess its 48....bcz the smallest 2 digit num that sum 17 is 98.....so the no of combinations of their sum is 48....

Is this solution Helpfull? Yes | No (1)  

Deepak singh  (8 years ago)

No of 2 digits=2
No of 3 digits=fix first hundreds digit
When it is 1,we have 5 ways
I.e 187,188,178,197,179....
Similarly
For 2. 4
For 3. 7
For 4. 6
For 5. 7
For 6. 8
For 7. 9
For 8. 10
For 9. 9

Total = 65+2= 67

Is this solution Helpfull? Yes | No (4)  

ashish  (8 years ago)

x+y+z=17

so no of possible solutions is given by
N+R-1 C R-1

N= 17 R= 3
so ans = 171

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Manisha Choudhary  (8 years ago)

Ans is 171

Is this solution Helpfull? Yes | No   

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