Latest Elitmus Aptitude Question SOLUTION: chakkar and ghanchakkar , two guys running in a circle, one in clockwise and other in anticlockwise direction. Chakkar completes 1 km in 4 min. , so with what speed should ghanchak

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(#M40157179) ELITMUS Numerical Ability question Keep an EYE

chakkar and ghanchakkar , two guys running in a circle, one in clockwise and other in anticlockwise direction. Chakkar completes 1 km in 4 min. , so with what speed should ghanchakkar run so that they cross each other exactly 24 times ?

Asked In Elitmus Pulkit Garg (8 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Amit karmakar  (8 years ago)

question is incomplete, unless and untill the radius of circular track is not given, we can`t solve this question....

Is this solution Helpfull? Yes (16) | No (1)  

mirza shamim  (8 years ago)

can any one help in out in this question

Is this solution Helpfull? Yes (2) | No   

shuvashini  (7 years ago)

Since chakkar and ghanchakkar move in opposite direction along the circle,so they will first meet at a sum of one round between the two.
Relative Speed of chakkar and ghanchakkar=(sc+sg)=24
sc=1/(4/60)=15round/hr
therefore, sg+15=24
sg=9 round/hr

Is this solution Helpfull? Yes (2) | No   

amar kakde  (8 years ago)

6 min per min

Is this solution Helpfull? Yes (1) | No (15)  

abdullah imran  (8 years ago)

when they are running in opposite direction then no of distinct meeting points =Sum of ratio of speeds in simplest form.
Now speed of Chakkar = 25/6 m/s. Let the ratio of speed of Chakkar and ghanchakkar be k then (25/6)/ghanchakkar=k so ghanchakkar=25/6k... So

24= 25/6 + 25/6k...-->>k=25/119
So ghanchakkar= 25/6k= (25*119)/(6*25)=119/6 m/s-->>> ans

Is this solution Helpfull? Yes (1) | No (4)  

venkatalakshmiparimala  (8 years ago)

Ghanchakkar runs 1 and half km per minute so after 36 minutes i.e ghanchakkar runs 13 1/2 km to meet chakkar

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sugandh  (7 years ago)

what are the options?

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alan  (7 years ago)

for one round by chkr, ganchkr makes 24 rounds. speed of chkr is 25/6 m/s.
Let total circumference be d therefore
d/(25/6)=24d/(speed of ghckr)
speed=100m/s that is 6km/min

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