Latest Elitmus Aptitude Question SOLUTION: loge(e(e(e....)^1/4)^1/4)^1/4

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(#M40157504) ELITMUS Numerical Ability question quants Keep an EYE

loge(e(e(e....)^1/4)^1/4)^1/4

Asked In Elitmus SHUBHAM (7 years ago)

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amit maurya  (7 years ago)

let us assume [log(e(e(e..)^1/4)^1/4)^1/4] = x
now as log m^n = n log(m)
we can write it as 1/4[log(e(e(e...)^1/4)^1/4)] = x
now 1/4[log(e)+log(e(e..)^1/4)^1/4)] = x
now we can see that it is again our question so we can replace it as x
so 1/4(1+x)= x
=> 4x = 1+x
=> x= 1/3

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