Latest Self Aptitude Question SOLUTION: I have 24.3 kg of apples, 1.7 kg banana, 0.04 kg grapes, 12.55 kg orange, 0.89 kg mango and 7.9 kg kiwi , a total of 47.38 kg of all fruits. some one ate 43.56 kg of fruits and I l

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(#M40157662) SELF Numerical Ability question Basic Maths Keep an EYE

I have 24.3 kg of apples, 1.7 kg banana, 0.04 kg grapes, 12.55 kg orange, 0.89 kg mango and 7.9 kg kiwi , a total of 47.38 kg of all fruits. some one ate 43.56 kg of fruits and I left with 3.82 kg.
Now how to calculate the amount of each fruit eaten (in terms of mass, kg)
very confusing

Sameer (7 years ago)

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Nisarg Shah  (7 years ago)

Apples 24.3
Banana 1.7
Grapes 0.04
Orange 12.55
Mango 0.89
Kiwi 7.9
Total 47.38
Above mentioned is the data available from the Question
Now lets take out the percentage of what amount of fruits someone ate. i.e. 43.56 will be how many % of 47.38
So (43.56*100)/47.38 = 91.93752638
Now, lets calculate the total fruits eaten.
i.e. (24.3*91.93752638)/100 For apple.
i.e. 22.34081891
Similarly for all fruits it is as below
24.3 *91.9375263824398/100= 22.34081891
1.7 *91.9375263824398/100= 1.562937949
0.04 *91.9375263824398/100= 0.036775011
12.55 *91.9375263824398/100= 11.53815956
0.89 *91.9375263824398/100= 0.818243985
7.9 *91.9375263824398/100= 7.263064584
Hence total of
22.34081891
1.562937949
0.036775011
11.53815956
0.818243985
7.263064584
=
43.56

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