Latest Elitmus Aptitude Question SOLUTION: If a cistern has 3 pipes of 1 cm , 4/3 cm and 2 cm thickness ...where the pipe with 2 cm thickness can fill the cistern in 2 hrs and 2 min..then in how much time they can fill the

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Pipes and Cistern

Elitmus Question Papers:

(#M40157808) ELITMUS Numerical Ability question Keep an EYE

If a cistern has 3 pipes of 1 cm , 4/3 cm and 2 cm thickness ...where the pipe with 2 cm thickness can fill the cistern in 2 hrs and 2 min..then in how much time they can fill the tank?

Asked In Elitmus Sniper (7 years ago)

Unsolved Read Solution (12)

Is this Puzzle helpful?   (9)   (5) Submit Your Solution Pipes and Cistern

Read Solution (12) :

dhanenkula  (7 years ago)

2cm can fill in 122min
thickness inversly propotional to time
total thickness of the pipe=1+4/3+2=4.3
we know that 2cm can fill in 122min
for 4.3cm time =56.7min

Is this solution Helpfull? Yes (13) | No (2)  

abhishek  (7 years ago)

total efficiency of all the 3 pipes in 1 min when opened together = 1/122+1/244+4/(244*3) =13/732 part of the cistern =732/13 mins = 56.3 mins

Is this solution Helpfull? Yes (6) | No (1)  

Devendra Nagar  (7 years ago)

its innerverse of its area .So
(4+16/9+1)T=4*122.
T =72 minutes.

Is this solution Helpfull? Yes (1) | No (5)  

naresh makkena  (7 years ago)

pipe a= 3/3 cms
pipe b=4/3 cms
pipe c=6/3 cms
given that pipe c takes 122 minutes
so for 122 parts 122*6=732
at a time three pipes means 6+4+3=13 parts
so 732/13 = 56.3 minutes

Is this solution Helpfull? Yes (1) | No   

ritu  (7 years ago)

1 hr ..lcm

Is this solution Helpfull? Yes | No (8)  

Avinash Singh  (7 years ago)

2 cm can fill in 122 min
it means, 1 cm can fill in 61 min and 4/3 cm can fill in 81.33 min.
find part in 1 min for each like this, for 2 cm fill in 1 min = 1/122 = 0.0081
now add each part and you got 0.0368, so together 3 pipes can fill 0.0368 part in 1 min
divide it by 1, and you got 27.17 min. that should be an answer.

Is this solution Helpfull? Yes | No (14)  

Asit kumar sahoo  (7 years ago)

for 2 cm pipe surface area @(pai)=122 min
for 1 cm pipe S A=0.25@
for 4/3 pipe S.A=1.77@
so 3@=122/3=40.66-~40min(apx)

Is this solution Helpfull? Yes | No (2)  

Anurag  (7 years ago)

2cm thick pipe can fill in 2hrs 2 min(61/30hr) ==> 1cm fills in 1hr 1 min(61/60hr) and 4/3cm fills in 4/3hr 4/3min (61/45hr)
So, (i) 61/30 hr --> 1 tank ==> 1hr --> 30/61 part ; (ii) 1hr --> 60/61 part (iii) 1hr --> 45/61 part
Therefore, in 1hr 3 pipes can fill ---> 135/61 part
So, time taken = 61/135 hrs = 26.8 min

Is this solution Helpfull? Yes | No (1)  

akhilnaarajkn  (7 years ago)

Any one know interview pattern for Associate trainee for e-Litmus?? Please reply fast

Is this solution Helpfull? Yes | No (1)  

PRIYABRATA MUKHERJEE  (7 years ago)

let us assume,x cm height of liquid can pass in all the pipes in one minute.
so,volume of the tank is=3.14*2*2*x*122(as 2 hours 22 mins=122 mins)
let say,y mins will be needed to fill the tank using all the pipes..
so,volume of the tank would be,3.14*x*(2*2+1*1+4/3*4/3)*y
so, both volumes are equal.
after solving,y=72 mins or 1hr 12 mins

Is this solution Helpfull? Yes | No (1)  

Naveen babu  (7 years ago)

capacity of pipes is not given........ we cannot say ,it depends upon force of water

Is this solution Helpfull? Yes | No (1)  

Ishank choudhary  (4 years ago)

we can do approximation to reduce calculation of fractions
2cm -> 2hr
4/3cm -> 3hr
1cm -> 4hr
took L.C.M of 2,3,4 = 12
divide 12/2+12/3+12/4 =13
12/13hr or 55.58 min.

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.