Latest MBA Aptitude Question SOLUTION: (10^10+10^10^2+10^10^3+10^10^4+10^10^5+10^10^6+10^10^7+10^10^8+10^10^9+10^10^10)/7 what will be reminder??

1) 1
2) 4
3) 5
4) none of this

• Placement Papers
• /
• MBA

MBA Question Papers:

(#M40015818) MBA question number systems, progressions Keep an EYE

(10^10+10^10^2+10^10^3+10^10^4+10^10^5+10^10^6+10^10^7+10^10^8+10^10^9+10^10^10)/7 what will be reminder??

1) 1
2) 4
3) 5
4) none of this

Asked In MBA (11 years ago)

Unsolved Read Solution (1)

Is this Puzzle helpful?   (1)   (0) Submit Your Solution

Read Solution (1) :

Divyesh Saraf  (6 years ago)

take 1st term 10^10/7 will give remainder as 10/7 = 3
therefore, 3^10/7 equivalent to (3^3)^3.3/7
=> (3^3)^3.3/7 = (27)^3.3/7
27 divided by 7 give remainder as -1
=> (-1)^3.3/7 = (-1).3/7
now,-1 can be replaced by 6 as -1+7=6
=> 6.3/7 = 18/7
=> 18/7 = 4
similarly every term will give remainder 4 when divided by 7
therefore, 4+4+4+4+4+4+4+4+4+4/7 = 40/7
and 40/7 gives remainder as 5

Ans is 5

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.