Latest IBM Aptitude Question SOLUTION: I attended the drive on 1 feb. 2017. 1.) 28,17,23,17,26,16,22,16,24,15,21,15 2.) 1/5,1/2,1/3,2/5,1,2/3,3/5,11/2,1,4/5 3.) -3,-6,-9,-82,-80,-30,-33,-36,-55,-53,-24 4.) 34.274,34.274

1) 28,17,23,17,26,16,22,16,24,15,21,15
Make this in 4 parts of series
28, 26, 24, 22(Ans)
17, 16,15 Fully Solved
23,22,21 Comment if you have any quarries
17,16,15
ans 22
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2) 1/5,1/2,1/3,2/5,1,2/3,3/5,11/2,1,4/5
Make it into three part
1/5,2/5,3/5,4/5
1/2,2/2,3/2,4/2(ans)
1/3,2/3,3/3
Ans 2
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3) -3,-6,-9,-82,-80,-30,-33,-36,-55,-53,-24
-3,-6,-9 difference=-3
-82,-80, difference=-2
-30,-33,-36 difference=-3
-55,-53 difference=-2
-24 so next difference also -3 i.e -24-3=-27
ans -27
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4) 34.274,34.2744,34.2784,34.3184
34.2744-34.274 = .0004
34.2784-34.2744= .0040
34.3184-34.2784 = .0400
x - 34.3184 = .4000
so x = 34.3184 + .4000 = 34.7184
ans = 34.7184
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5) 8,16,3,27,4,8,7,19,2,0,7
8+16+3=27
4+8+7=19
2+0+7=9
ans = 9
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6) -3,6,1,-2,4,-1,-1,2,-3
make this series into 3 parts
-3, -2, -1, 0(ans)
6, 4, 2, 0
1, -1, -3, -5
ans 0
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7) 2,3,10,15,26
2= (1*1)+1
3= (2*2)-1
10= (3*3)+1
15= (4*4)-1
26= (5*5)+1
x= (6*6)-1
ans = 35
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8) 0.03,0.0018,0.00108,0.00648,0.3888
0.0018/0.03= 0.06
0.00108/0.0018= 0.6
0.00648/0.00108=6
0.3888/0.00648=60
x/0.3888 = 600
so x = 600*0.3888 = 233.28
ans 233.28
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9) 0,1,2,0.5,2,3,5,1,2,0,2,1,4,2,3
for 0,1,2,0.5 - -> 0+1 = 1, 1/2 = 0.5
for 2,3,5,1 ---> 2+3 = 5, 5/5 = 1
for 2,0,2,1 ---> 4+2 = 6, 6/3 =2
ans 2
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10) 1.4,2.4,2.4,4.4,8.8,11.8,35.4,39.4
1.4+1=2.4
2.4*1=2.4
2.4+2=4.4
4.4*2=8.8
8.8+3=11.8
11.8*3=35.4
35.4+4=39.4
39.4*4=157.6
ans. 157.6
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11) 5,5,7,7,9,11,11,13,13,17,17,15,19,17

wrong series i think
it should be 5,5,7,7,9,11,11,13,13,17,15,19,17,?
1st series difference is +2 ----> 5,7,9,11,13,15,17
2nd series difference is +2 then +4 ---> 5,7,11,13,17,19,23
ans 23
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12) 2,1,2,3,8,0,1,9,1,2
2^1=2, 2^3=8, 8^0=1, 1^9=1, 1^2=1
ans 1
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13) 37,73,9,49,58,85,25,64,29,92
37 reverse 73 then digit square 3^2 and 7^2
37 rev 73 3^2, 7^2
58 rev 85 5^2, 8^2
29 rev 92 2^2(ans)
ans 4.
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14) 3,5,2,3.5,7,4,6,3,4.5,9,1.5
explanation
(5-2), 5, 2, (5+2)/2, (5+2), (6-2), 6, 3, (6+3)/2, 6+3,(x-2)=1.5
so ans = 1.5+2 = 3.5
ans 3.5
15.) 2,1,2,3,2,9,9,0,1,1,9
2,1,2^1,3,2,3^2,9,0,9^0,1,9,1^9
ans 1
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16.) 36,42,16,20,36,42,4
6^2,6*7,4^2,4*5,6^2,6*7,2^2,2*3
ans 6
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17.) 11,8,17,14,23,24,31,32,35
11,11-3,17,17-3,23,23+1,31,31+1,35,35+5
ans 40
or
11,23,35 -difference 12
8,24,40(ans) difference 16
-----------------------------------------------------------------
18.) 25,13,39,17,51,19,57,15,45
25 - 13 = 12
39 - 17 = 22
51 - 19 = 32
57 - 15 = 42
45 - x = 52
ans -7

5) make a group of 4 terms, 4th term is the sum of remaining 3 terms.
8+16+3=27
4+8+7=19
2+0+7=9
ans is 9.

1)22
2)2
3)-27
4)34.7184
5)9
6)0
7)35
8)233.28
9)2
10)157.6
11)2
12)1
13)4
14)3.5
15)1
16)8
17)?
18)-7

7. 1^2+1=2
2^2-1=3
3^2+1=10
4^2-1=15
5^2+1=26
6^2-1=35(aNS)

8.) 0.03,0.0018,0.00108,0.00648,0.3888
0.03*0.06=0.0018
0.0018*0.6=0.00108
0.00108*6=0.00648
0.00648*60=0.3888
0.388*600=233.28

I have attended ibm gbs offcampus drive held at cmr college on 19 th Feb 2017 apt and English ra simple
Java question I got is to find the next to the last word in a string
So guys be aware of string methods

6.) -3,6,1,-2,4,-1,-1,2,-3
-3,6,1,-|2,4,-1, | -1,2,-3

observe first digit from each set=-3,-2,-1
observe second digit from each set=6,4,2
observe third digit from each set=1,-1,-3,3
So from First set We Observe that ans =-3,-2,-1,0(ans)

2) 1/5,1/2,1/3,2/5,1,2/3,3/5,11/2,1,4/5...
series is 1/5,2/5,3/5,4/5....
1/2,(2/2) 1,2/3,(4/2) 2 .....11/2 is wrong it may be 3/2
1/3,2/3,(3/3) 1,4/3.....
so answer is 4/2 is 2

3.) -3,-6,-9,-82,-80,-30,-33,-36,-55,-53,-24
-3,-6,-9 difference=-3
|,-82,-80, difference=-2|-30,-33,-36 difference=-3|,-55,-53 difference=-2|,-24 so next difference also -3 i.e -24-3=-27=Ans

3.) -3,-6,-9,|-82,-80|,-30,-33,-36|,-55,-53|,-24
3. 3. 2. 3. 3. 2
Ans:21

4.) 34.274,34.2744,34.2784,34.3184
+4. +40. +400.
Ans:34.7184

1.) 28,17,23,17,26,16,22,16,24,15,21,15
(28,26,24,_) (23,22,21)
first series: 28,26,24,
second series: 23,22,21,
ans->22
3.) -3,-6,-9,-82,-80,-30,-33,-36,-55,-53,-24
(-3,-6,-9)(-82,-80)(-30,-33,-36)(-55,-53)(-24,_)
first series: (-3,-6,-9)(-30,-33,-36)(-24,_,_) => minus 3 in prev. number
second series: (-82,-80)(-55,-53) =>add 2 in prev. number
Ans-> -27

12.) 2,1,2,3,8,0,1,9,1,2
2^1=2, 2^3=8, 8^0=1, 1^9=1, 1^2=1
13.) 37,73,9,49,58,85,25,64,29,92
37,73,3^2,7^2,58,85,5^2,8^2,29,92
Alternate series of 3^2,5^2,7^2...
Other series of7^2,8^2,9^2...
Ans=7^2=49
15.) 2,1,2,3,2,9,9,0,1,1,9
2^1=2,
3^2=9,
9^0=1,
1^9=1
16.) 36,42,16,20,36,42,4
36+6=42, 16+4=20
36+6=42, 4+4=8
Ans:8

16: 6
as because 36=6*6; 42 = 6*7; 16 = 4*4; 20 = 4*5; .......... 4 = 2*2; so 2*3 =6;;;;
i.e 6*6, 6*7, 4*4, 4*5, 6*6, 6*7, 2*2, 2*3......
as what i conclude from that....

9.take first four digits from series: 0,1,2,0.5
0+1=1,1/2=0.5
2,3,5,1
2+3=5,5/5=1

2,0,2,1

2+0=2,2/2=1

4,2,3,?

4+2=6,6/3=2

ans:2

17.)11,8,17,14,23,24,31,32,35..next digit 32 because (11-3=8,17-3=14),(23+1=24,31+1=32),(35-3=32)

Prime nos are---: 11 , 13, 17 , 19, 23 ,
29, 31, 37, 41,43
Sequence Given--: 11, 8, 17, 14, 23, 24,
31, 32, ??
Sequence Formation : alternate prime
num -5
ie Seq Formed as follows :
11 , 13-5, 17 , 19-5, 23 , 29-5, 31 ,
37-5,41,43-5
====>that equals Given Sequence :
11,8,17,14,23,24,31,32
next will
so answer will be 41 38

1.alternate sereis
28-5=23,23+3=26,26-4=22,22+2=24,24-3=21,21+1=22

10>
1.4+1=2.4
2.4*1=2.4
2.4+2=4.4
4.4*2=8.8
8.8+3=11.8
11.8*3=35.4
35.4+4=39.4
39.4*4=157.6
ans. 157.6

1.22
3.-27
4.34.7184
7.35
8.233.28
9.3
10.157.6

7.) 2,3,10,15,26
2*1=2
3*1=3
2*5=10
3*5=15
2*13=26
3*13=39(ans)

4) 34.274
00.0004
-----------------
34.2744
00.0040
-----------------
34.2784
00.0400
------------------
34.3184
00.4000
------------------
34.7184
------------------

ANS IS 34.7184

17) answer for 17 th que is: 32
because, 11-8=3
17-14=3, and
23-24=-1
31-32=-1 ; Hence the diff between the alternate no is 3 and -1.
So, we have to subtract 3 from 35.
Hence the ans becomes 32

1=>22(they are doublets the difference will be (11 6 10 6 9 6 )next difference should be 8)
2=>2 eight term is not 11/2 it is (1 1/2) i.e.., 3/2)
3=> -27 (check the triplet difference then doublet difference)
4=>34.7184 (check for +0004,+0040,+0400,+4000)
5=>9 (take quardlets sum of first three=fourth)
6=>0 (check 1st,4th,7th terms)
7=>35 (check difference of terms 1 7 5 11 it will be 9)
8=>233.28(mutliply by .06 .6 6 60 600)
9=>0.5(take quardlets substract third from second and divide by 2i.e..,(3-2)/2)
10=>157.6 (suma nd product of consecutive terms)for more refer PRIYA MITRA solution.
11=>23 (check series their is gap of 6)

please send me the explanation for 2

Answer of 17th que is 38
11,8,17,14,23,24,31,32,35
8-11= -3,
14-17= -3
24-23=1
32-31=1
35-32=3
therefore 38-35=3

18). 25-12=13
39-22=17
51-32=19
57-42=15
45-52=-7(answer)

1.) consider alternate number in the series
You can observe 17 17 16 16 15 15
answer is 14

37,73,9,49,58,85,25,64,29,92,?
1st 2 elements are 37,73
3rd and 4th element is consist of 3^2=9,7^2=49
so if we consider 29 and 92 then we can say 2^2=4 and 9^2=81
so now we have 37,73,9,49,58,85,25,64,29,92,4,81
so 2 is the ans

Could someone please explain solution for 11)?
Thank You

37,73,3^2,7^2......
Next 29,92,2^2,9^2
Answer is:2^2=4

28 17 23 17 (28-23=5)
26 16 22 16 (26-22=4)
24 15 21 15 ( 24-21=3)
22 14 20 14 (22-20=2)

hence series=28,17,23,17,26,16,22,16,24,15,21,15,22,14, 20 ,14

9> 0.03 * 0.06 = 0.0018
0.0018 * 0.6 = 0.00108
0.00108 * 6 = 0.00648
0.00648 * 60 = 0.3888.
0.3888*600=233.28

1. 28,23,26,22,24,21
28-23=5,26-23=3,26-22=4,24-22=2,24-21=3,22-21=1
answer is 22