Latest MBA Aptitude Question SOLUTION: Two series A (a1, a2, a3, ....an) and B (b1, b2, b3, ....bn) are in A.P. such that an – bn = n – 1, where an stands for the nth term of the series A, and bn for the n

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(#M40016117) MBA question number systems, progressions Keep an EYE

Two series A (a1, a2, a3, ....an) and B (b1, b2, b3, ....bn) are in A.P. such that an – bn = n – 1, where an stands for the nth term of the series A, and bn for the nth term of the series B. It is also known that a6 = b8. Find the value of a101 – b121.

1) -45
2) 47.5
3) 50
4) -47.5
5) Cannot be determined

Asked In MBA (11 years ago)

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