Latest Elitmus Aptitude Question SOLUTION: a,b,c walk 1km in 5 min,8min and 10min respectively.c starts walking from a point,at a certain time,b starts from the same point 1 min later and a starts from the same point 2 min

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(#M40164399) ELITMUS Numerical Ability question Keep an EYE

a,b,c walk 1km in 5 min,8min and 10min respectively.c starts walking from a point,at a certain time,b starts from the same point 1 min later and a starts from the same point 2 min later than c.then a meets b and c after.?

Asked In Elitmus Sniper (7 years ago)

Unsolved Read Solution (3)

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Read Solution (3) :

Ankit  (7 years ago)

A walks 1 km in 5 min.
Then, distance covered by A in 1 min = 1000/5 = 200 m

B walks 1 km in 8 min.
Then, distance covered by B in 1 min = 1000/8 = 125 m

C walks 1 km in 10 min.
Then, distance covered by C in 1 min = 1000/101 = 100 m

Let A meets B and C in x and y min, respectively.

Then
Distance covered by C in(x + 2) min = Distance covered by A in x min
100(x + 2) = 200 x
100 x + 200 = 200 x
200 = 100 x
x = 200/100 = 2 min

for A and B
Distance covered by B in (y + 1) min = Distance covered by A in y min
125(y + 1) = 200y
125y + 125 = 200y
125 = 200y - 125y
125 = 75y
y =5/3 minut.

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ratul  (7 years ago)

speed of a,b,c =1/5,1/8,1/10 km/min respectively
c covers in 2mins=2/10 km
b covers in 1 min=1/8km
then a started
speed diff between a & b=(1/5-1/8)=3/40km/min
in t=d/s=(1/8) / (3/40) =5/3 min =1min 40 sec a will cover the initial gap between a&b (ans)
speed diff between a & c=1/10 km/min
in t=d/s=(1/5) / (1/10) =2 min a will cover the initial gap between a&c (ans)

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greeshma  (7 years ago)

speed of a=1/3, b =5/24 ,c=1/6 m/s [ 1km=100m and 1 min=60s]
consider the time as
for c= t+120 [2 min =120s ]
for b=t+60 [ 1min=60s ]
for a=t
a meets b , Then both distance are equal.so we can use speed*time.
[t+60]*5/24=t*24
t=100s [1min 40s]
a meets c
[t+120]*1/6=t*1/3
t=120s [2min].

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