Latest Elitmus Aptitude Question SOLUTION: if 47.2506=4A+7/B+2C+5/D+6E,then the value of 5A+3B+6C+D+3E is what?

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(#M40164479) ELITMUS Numerical Ability question Keep an EYE

if 47.2506=4A+7/B+2C+5/D+6E,then the value of 5A+3B+6C+D+3E is what?

Asked In Elitmus Sniper (7 years ago)

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KHOMENDRA kumar  (7 years ago)

4*A + 7/B + 2*C + 5/D + 6*E =47.2506
=> 4 * A + 7/B + 2 *C + 5/D + 6*E = 40 + 7 + 0.2 + 0.05 + 0.0006
Comparing the terms on both sides, we get :
4*A =40, 7/B = 7, 2*C = 0.2, 5/D = 0.05, 6*E = 0.0006
A = 10,
B = 1,
C = 0.1,
D = 100,
E = 0.0001.
5*A + 3*B + 6*C + D + 3*E =(5*10) + (3*1) + (6*0.1) +100 +(3*0.0001)
=50 + 3 + 0.6 + 100 + 0.003 = 153.6003.

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rajat bhawsar  (6 years ago)

why did you take d=100 please clear my doubt......

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parul gupta  (7 years ago)

4×10+7/1+2/10+5/100+6/10000
A=10;B=1;C=1/10;D=100;E=1/10000
ans is 153.6003

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bryan  (6 years ago)

@ RAJAT
5/d = 5/100
d ==> 100

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