Latest TCS Aptitude Question SOLUTION: Predict the output of following code: main() { int i=10; printf(“%d,%d”,++i,++i); } 1. 11,12 2. 12,11 3. 10,11 4. 11,10

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Predict the output of following code:
main()
{
int i=10;
printf(“%d,%d”,++i,++i);
}
1. 11,12
2. 12,11
3. 10,11
4. 11,10

Asked In TCS Ashish (6 years ago)

Unsolved Read Solution (11)

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Read Solution (11) :

Rajat Agarawal  (6 years ago)

the answer will be 12,12.
As both are pre increment operators.

Is this solution Helpfull? Yes (17) | No (6)  

Mydhily Sunayana  (5 years ago)

The answer is 12,11 since the printf statement executes from right to left.

Is this solution Helpfull? Yes (11) | No (7)  

aniket jain  (5 years ago)

ans is 12 12 because printf prints from right to left
so it will first increase the value twice i.e from 1st ++i it will be 11 than for another ++i it will be 12 and than after this both %d will take this 12 as the value and will print

Is this solution Helpfull? Yes (8) | No (1)  

Akshara M.A  (6 years ago)

The answer is 11,12.

Is this solution Helpfull? Yes (6) | No (6)  

Aman  (5 years ago)

++i is the prefix increment operation.
initially i=10
first , ++i = ++10 = 10+1 = 11
second , ++i = ++11 = 11+1 = 12
So, Output is : 11 , 12.

Is this solution Helpfull? Yes (6) | No (8)  

Ravali pillalamarri  (5 years ago)

Printf statement executes from the last so first it prints 11 then prints 12
Ans:12 11

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venkata reddy  (5 years ago)

12,11 since printf print from right to left

Is this solution Helpfull? Yes (1) | No (1)  

Ramya  (5 years ago)

In the above program output should (11,12) because it follows pre_increment

Is this solution Helpfull? Yes (1) | No (3)  

Soundesh  (5 years ago)

Printf frist print value of i and after increase ++i so answer
I=10 after i=11 after increasei=12
Answer is 10 and 11

Is this solution Helpfull? Yes | No (1)  

rakesh pabolu  (5 years ago)

Here unary minus (or negation) operator is used twice. Same math rules applies, ie. minus * minus = plus.
Note: However you cannot give like --2. Because -- operator can only be applied to variables as a decrement operator (eg., i--). 2 is a constant and not a variable.

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teja  (5 years ago)

11 ,12,first of aall ++i means increment i so int i will incremen two times because two ++i's are there

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