Latest TCS Aptitude Question SOLUTION: How many of the following are invalid variable name? NUMBER first.name midname. _num ​ 93num num93 last name ​ nUMBER 4321 1. 5 2. 3 3. 2 4. More than 5

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How many of the following are invalid
variable name?
NUMBER
first.name
midname. _num ​ 93num
num93
last name ​ nUMBER
4321
1. 5
2. 3
3. 2
4. More than 5

Asked In TCS Ashish (6 years ago)

Unsolved Read Solution (15)

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Read Solution (15) :

ankur kumar garg  (5 years ago)

No of invalid variable is 4. the nvalid variables are the following
first.name // special character other than '_' is not allowed
midname._num 93num // special character other than '_' is not allowed
last name nUMBER //space is not allowed
4321 // variable name should start with either an alphabet or '_' character

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sanket chidrewar  (6 years ago)

All variable names must begin with a letter of the alphabet or an. underscore( _ ). ...
After the first initial letter, variable names can also contain letters and numbers. ...
Uppercase characters are distinct from lowercase characters. ...
You cannot use a C++ keyword (reserved word) as a variable name.

soo 3 of these are invalid
ans:-option 2

Is this solution Helpfull? Yes (4) | No (2)  

Kousalya  (5 years ago)

#include
int main()
{
Int a, b;
Printf("enter the values if a and b") ;
Scanf("%d %d", &a, & b) ;
b=a+b;
a=b-a;
b=b-a;
printf("%d%d", a, b) ;
Return(0);
}

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Monisha  (5 years ago)

Characters Allowed :
Underscore(_)
Capital Letters ( A – Z )
Small Letters ( a – z )
Digits ( 0 – 9 )
Blanks & Commas are not allowed
No Special Symbols other than underscore(_) are allowed
First Character should be alphabet or Underscore
Variable name Should not be Reserved Word.
Dot(.), Spaces are not allowed in variable names so answer is option 1

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  (6 years ago)

Ans:1
Because variable name must start with _ or
Alphabet
. And spaces not allowed in variable name

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vinika gupta  (6 years ago)

4
because no special characters are allowed

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Dhivyaa  (6 years ago)

ans-option 2
because, var name should no starts with numerics and var name doesnot accepts space so 3 variable names in the list are invalid

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sindhu  (4 years ago)

a variable name should not start with a capital letter,number or any symbol except undercore and space is not allowed
hence,the answer is 5

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pooja raj  (5 years ago)

Ans will be 1.5

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sai kiran Kolusu  (5 years ago)

answer: Option 2. 3
because variable names can be started only with alphabets or underscores.
There should be no spaces present in between the variable name

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Veera Narayanamma Kamani  (5 years ago)

two variable declarations are ok.Because of only these two follow variable name declaration rules

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sirisha veerapaneni  (4 years ago)

i think its 3

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princika  (4 years ago)

Characters Allowed :
Underscore(_)
Capital Letters ( A – Z )
Small Letters ( a – z )
Digits ( 0 – 9 )
Blanks & Commas are not allowed
No Special Symbols other than underscore(_) are allowed
First Character should be alphabet or Underscore
Variable name Should not be Reserved Word.

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gaurav singh  (4 years ago)

ans- option 1

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Pallavi  (2 years ago)

4 are invalid
first.name
midname._num 93num
last name nUMBER
4321
these are against the string rules. A string does not have space or (.) or number in it

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