Latest Elitmus Aptitude Question SOLUTION: A two digit number is 1/3 rd of itself.consider unit digit is 'a' and tens digit is 'b'.How many two digits is possible?

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(#M40165374) ELITMUS Numerical Ability question Keep an EYE

A two digit number is 1/3 rd of itself.consider unit digit is 'a' and tens digit is 'b'.How many two digits is possible?

Asked In Elitmus Mounika (6 years ago)

Unsolved Read Solution (5)

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  (6 years ago)

the question is actually if the two digits of a 2 digit no are multiplied and product is 1/3rd of the actual no. then find the no of such no?
answer is 2
15 and 24 are the only two no which satisfy the given condition

Is this solution Helpfull? Yes (11) | No (4)  

Saurav  (6 years ago)

wrong question!!!!
how can a number be 1/3rd of itself

Is this solution Helpfull? Yes (6) | No   

Mr Sumit  (6 years ago)

do not ask incomplete questions

Is this solution Helpfull? Yes (3) | No   

JAY SYKES  (6 years ago)

question is incomplete or wrong

Is this solution Helpfull? Yes (1) | No   

  (6 years ago)

The above question is wrong !
May be the question look like this
In a two-digit number the tens’ digit is 1 more than the units’ digit. The number itself is 6 times the sum of the digits. Find the number.
A number with two digits can be written as AB where the A and the B are the digits in the tens and ones places. I set up one of the other questions you asked, I'll solve this one out in case you need to see how it's done.

A = B + 1

AB can be rewritten as 10A + B

10A + B = 6(A + B)

This gives me a system of equations. Since the first equation gives me A in terms of B, I'll replace the As in the second equation with B + 1. The first equation is saying that "A is the same thing as B + 1".

So dealing with the second equation:

10A + B = 6(A + B)

10(B + 1) + B = 6(B + 1 + B)

10B + 10 + B = 6B + 6 + 6B

11B + 10 = 12B + 6

B = 4

Then A is one more than this, so A = 5.

The number is 54.

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