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(#M40165458) ELITMUS Numerical Ability question Keep an EYE

The maximum number of factors below 600 are?

Asked In Elitmus Babita Bisht (6 years ago)

Solved Govind kumar Read Solution (8)

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Read Solution (8) :

sivasai reddy  (6 years ago)

ans: 24
600= 2^3∗3∗5^2
number of factor (3+1) (1+1) (2+1)=24

Is this solution Helpfull? Yes (16) | No (1)  

Govind kumar  (6 years ago) Best Solution

If x=am∗bn∗cp...
where a, b, c, ... are the prime factors of x, then the number of factors of x is
(m+1)(n+1)(p+1)...

This is because any factor can be made by selecting 0 to m numbers of a (in m+1 ways), 0 to n numbers of b (in n+1 ways) and so on.

Since 600=23∗3∗52
Total number of factors of 600 = (3+1)(1+1)(2+1) = 24

Is this solution Helpfull? Yes (7) | No (2)  

kancharla srinadh  (5 years ago)

it is not about factors of 600
question is wrong

Is this solution Helpfull? Yes (1) | No (1)  

vishwas  (5 years ago)

it's 23 since the factors should be less than 600.if the answer is 24 then 600 would be included which is wrong

Is this solution Helpfull? Yes (1) | No (1)  

poonam chandra  (6 years ago)

Factor of 600
(2^3)*(3^1)*(5^2)
(3+1)*(1+1)*(2+1)=4*2*3=24

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arvind patel  (5 years ago)

24
the factors of 600 are
(2^3)(5^2)(3)
then total factor will be
4*3*2=24

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Abhay  (9 Months ago)

Ans =24 ;its not about to include 600 or not only take 480 =2^5 x 3 x 5
Number of divisor= (6) x 2 x 2 = 24

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soyam mounika  (1 Month ago)

ans: 24
600 can be expressed as 2^3 *3^1 * 5^2
number of factors of 600 are (3+1) (1+1) (2+1)=24

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