Latest TCS Aptitude Question SOLUTION: What is the number of positive integers less than or equal to 2017 that have at least one pair of adjacent digits that are both even. For example 24,564 are two examples of such nu

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Arithmetic

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40165781) TCS Numerical Ability question advance Keep an EYE

What is the number of positive integers less than or equal to 2017 that have at least one pair of adjacent digits that are both even. For example 24,564 are two examples of such numbers while 1276 does not satisfy the required property. ans-738

Asked In TCS edwin (5 years ago)

Unsolved Read Solution (1)

Is this Puzzle helpful?   (11)   (10) Submit Your Solution Arithmetic

Read Solution (1) :

Srivenkatesan S  (4 years ago)

Answer:

738

Step-by-step explanation:

What is the number of positive integers less than or equal to 2017 that have at least one pair of adjacent digits that are both even.

Number should be at least 2 digits

2 digits numbers starting & ending with even number

Starting digits 2 , 4 , 6 , 8  Ending digit 0 2 , 4 , 6 , 8

4 * 5 = 20 numbers

3 Digit numbers

its necessary that Middle number is even number

0 2 4 6 8

1st digit even number 2 4 , 6 , 8   & 3rd digit any digit

5 * 4 * 10 = 200

3rd digit even number 0 2 4 6 8  & 1st digit any ( 1 to 9)

= 5 * 5 * 9 = 225

Repeated number here where 1st & 3rd digit even numbers

4 * 5 * 5 = 100 ( to be reduced)

3 Digit numbers = 200 + 225 - 100 = 325

in 4 digit number  1000 to 1999

1100 to 1999 again these 325 numbers  & additional 50 numbers where 2nd digit = 0 (1000 to 1099)

= 325 + 50 = 375 numbers

2000 to 2017  (1st two digits are even)

All 18 numbers    

Total number = 20 + 325 + 375 + 18 = 738

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.